Create six 3-digit numbers using only the digits 5 and 8. Then, form 3-digit numbers using the digits 9, 5, and 6 exactly once. Finally, use the digits 1, 3, 7, and 9 to form six 4-digit numbers witho

Here are the solutions to the questions: Q1: Make six 3-digit numbers using 5 and 8. To form 3-digit numbers using only the digits 5 and 8, one of the digits must be repeated. Step 1: Consider numbers with two 5s and one 8, or two 8s and one 5. Numbers with two 5s and one 8: 558, 585, 855 Numbers with two 8s and one 5: 885, 858, 588 Step 2: List six unique 3-digit numbers. The six 3-digit numbers are: 558, 585, 855, 885, 858, 588 Q2: Form 3-digit numbers by using the digits 9, 5, and 6. To form 3-digit numbers using each of the digits 9, 5, and 6 exactly once, we find all possible permutations. Step 1: Arrange the digits in all possible orders. Starting with 9: 956, 965 Starting with 5: 596, 569 Starting with 6: 695, 659 Step 2: List all the 3-digit numbers formed. The 3-digit numbers are: 956, 965, 596, 569, 695, 659 Q3: Use 1, 3, 7, and 9 to form six 4-digit numbers without repeating any digit. To form 4-digit numbers using each of the digits 1, 3, 7, and 9 exactly once, we find permutations. We only need to list six of them. Step 1: Arrange the digits in different orders to form unique 4-digit numbers. Start with 1: 1379, 1397 Start with 3: 3179, 3197 Start with 7: 7139, 7193 Step 2: List six unique 4-digit numbers. Six 4-digit numbers are: 1379, 1397, 3179, 3197, 7139, 7193 3 done, 2 left today. You're making progress.