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The image contains a numerical pyramid puzzle where each number is the sum of the two numbers directly below it. The bottom row is [2, 4, 6, 8, 10]. The question is to fill in the missing numbers in the pyramid.

Mathematics

ScanSolve AI Answer

Answer

244R=11244 \quad R = 11

Step-by-step solution

3 steps
  1. Determine how many times 23 goes into the first two digits 56.

    56÷23=256 \div 23 = 2 (since 23×2=46≤5623 \times 2 = 46 \leq 56 and 23×3=69>5623 \times 3 = 69 > 56)

    Multiply: 23×2=4623 \times 2 = 46

    Subtract: 56−46=1056 - 46 = 10

    Bring down the next digit 2 to get 102.

  2. Determine how many times 23 goes into 102.

    102÷23=4102 \div 23 = 4 (since 23×4=92≤10223 \times 4 = 92 \leq 102 and 23×5=115>10223 \times 5 = 115 > 102)

    Multiply: 23×4=9223 \times 4 = 92

    Subtract: 102−92=10102 - 92 = 10

    Bring down the next digit 3 to get 103.

  3. Determine how many times 23 goes into 103.

    103÷23=4103 \div 23 = 4 (since 23×4=92≤10323 \times 4 = 92 \leq 103 and 23×5=115>10323 \times 5 = 115 > 103)

    Multiply: 23×4=9223 \times 4 = 92

    Subtract: 103−92=11103 - 92 = 11

    No more digits remain.

    Quotient: 244, Remainder: 11

    244R=11244 \quad R = 11
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