The image contains a numerical pyramid puzzle where each number is the sum of the two numbers directly below it. The bottom row is [2, 4, 6, 8, 10]. The question is to fill in the missing numbers in the pyramid.

Step 1: Determine how many times 23 goes into the first two digits 56.
$56 \div 23 = 2$ (since $23 \times 2 = 46 \leq 56$ and $23 \times 3 = 69 > 56$)

Multiply: $23 \times 2 = 46$

Subtract: $56 - 46 = 10$

Bring down the next digit 2 to get 102.

Step 2: Determine how many times 23 goes into 102.
$102 \div 23 = 4$ (since $23 \times 4 = 92 \leq 102$ and $23 \times 5 = 115 > 102$)

Multiply: $23 \times 4 = 92$

Subtract: $102 - 92 = 10$

Bring down the next digit 3 to get 103.

Step 3: Determine how many times 23 goes into 103.
$103 \div 23 = 4$ (since $23 \times 4 = 92 \leq 103$ and $23 \times 5 = 115 > 103$)

Multiply: $23 \times 4 = 92$

Subtract: $103 - 92 = 11$

No more digits remain.

Quotient: 244, Remainder: 11

$\boxed{244 \quad R = 11}$