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Calculate the mean and median for the given set of figures related to average pay.

Mathematics

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6 parts
a(i)

24 GHC\text{24 GHC}

a(ii)

23 GHC\text{23 GHC}

a(iii)

22 GHC\text{22 GHC}

a(iv)

3.09 GHC\text{3.09 GHC}

b(i)

22 GHC\text{22 GHC}

b(ii)

3.09 GHC\text{3.09 GHC}

Step-by-step solution

15 steps

Here is the completed table and the calculations:

Completed Table:

Average pay (x)TallyNo. of people (f)fxx2^2fx2^2
18I118324324
21I121441441
22III3664841452
23II2465291058
25II2506251250
26I126676676
27I127729729
29II2588411682
∑f=13\sum f = 13∑fx=312\sum fx = 312∑fx2=7612\sum fx^2 = 7612

Part a(i)· 3 steps

Mean

Calculate, for this set of figures the

  1. Use the formula for the mean of grouped data.

    Mean(μ)=∑fx∑f\text{Mean} (\mu) = \frac{\sum fx}{\sum f}
  2. Substitute the sums from the table.

    μ=31213\mu = \frac{312}{13}
  3. Calculate the mean.

    μ=24\mu = 24

    The mean is 24 GHC\boxed{\text{24 GHC}}.

Part a(ii)

23 GHC\text{23 GHC}

Median

  1. Order the data points

    18, 21, 22, 22, 22, 23, 23, 25, 25, 26, 27, 29, 29

  2. Determine the position of the median.

    There are N=13N=13 data points.

    Median position=N+12-th value=13+12-th value=7-th value\text{Median position} = \frac{N+1}{2}\text{-th value} = \frac{13+1}{2}\text{-th value} = 7\text{-th value}
  3. Identify the 7th value in the ordered list.

    The 7th value is 23.
    The median is 23 GHC\boxed{\text{23 GHC}}.

Part a(iii)

22 GHC\text{22 GHC}

Mode

  1. Identify the value that appears most frequently in the data.

    From the frequency table, the value 22 appears 3 times, which is more than any other value.
    The mode is 22 GHC\boxed{\text{22 GHC}}.

Part a(iv)

3.09 GHC\text{3.09 GHC}

Standard deviation

  1. Use the formula for variance.

    Variance(σ2)=∑fx2∑f−(∑fx∑f)2\text{Variance} (\sigma^2) = \frac{\sum fx^2}{\sum f} - \left(\frac{\sum fx}{\sum f}\right)^2
  2. Substitute the sums from the table.

    σ2=761213−(31213)2\sigma^2 = \frac{7612}{13} - \left(\frac{312}{13}\right)^2
  3. Calculate the terms.

    σ2=585.5384615...−(24)2\sigma^2 = 585.5384615... - (24)^2 σ2=585.5384615...−576\sigma^2 = 585.5384615... - 576 σ2=9.5384615...\sigma^2 = 9.5384615...
  4. Calculate the standard deviation by taking the square root of the variance.

    Standard Deviation(σ)=σ2=9.5384615...\text{Standard Deviation} (\sigma) = \sqrt{\sigma^2} = \sqrt{9.5384615...} σ≈3.0884\sigma \approx 3.0884

    The standard deviation is 3.09 GHC\boxed{\text{3.09 GHC}} (rounded to two decimal places).


Part b(i)

22 GHC\text{22 GHC}

The new mean

If all the data sets are decreased by GHC 2, what will the following become?

  1. When a constant is subtracted from every data point, the mean also decreases by that constant.

    New Mean=Original Mean−2\text{New Mean} = \text{Original Mean} - 2
  2. Substitute the original mean.

    New Mean=24−2=22\text{New Mean} = 24 - 2 = 22

    The new mean is 22 GHC\boxed{\text{22 GHC}}.

Part b(ii)

3.09 GHC\text{3.09 GHC}

The new standard deviation

  1. Subtracting a constant from every data point shifts the entire distribution but does not change its spread or variability.

    Therefore, the standard deviation remains the same.

    New Standard Deviation=Original Standard Deviation\text{New Standard Deviation} = \text{Original Standard Deviation}
  2. Substitute the original standard deviation.

    New Standard Deviation≈3.09\text{New Standard Deviation} \approx 3.09

    The new standard deviation is 3.09 GHC\boxed{\text{3.09 GHC}}.

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