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Calculate for me the mean ,median and mode

Mathematics

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Answer

11.31\text{11.31}

9.17\text{9.17}

7.81\text{7.81}

Step-by-step solution

4 steps

To calculate the mean, median, and mode for grouped data, we first need to set up a table with class midpoints and cumulative frequencies.

Here's the data from the image:

Class IntervalFrequency (fif_i)
1-512
6-1030
11-159
16-207
21-256
26-304
  1. Prepare the table with midpoints and cumulative frequencies.

    We need the midpoint (xix_i) for each class and the cumulative frequency (CFCF). The total frequency N=∑fi=12+30+9+7+6+4=68N = \sum f_i = 12+30+9+7+6+4 = 68.

    Class IntervalFrequency (fif_i)Midpoint (xix_i)fixif_i x_iCumulative Frequency (CFCF)
    1-51233612
    6-1030824042
    11-1591311751
    16-2071812658
    21-2562313864
    26-3042811268
    TotalN=68N=68769
  2. Calculate the Mean.

    The formula for the mean of grouped data is:

    xˉ=∑fixiN\bar{x} = \frac{\sum f_i x_i}{N}

    Substitute the values from the table:

    xˉ=76968\bar{x} = \frac{769}{68} xˉ≈11.3088\bar{x} \approx 11.3088

    Rounding to two decimal places, the mean is 11.31\boxed{\text{11.31}}.

  3. Calculate the Median.

    The formula for the median of grouped data is:

    Median=L+(N2−CFf)×w\text{Median} = L + \left( \frac{\frac{N}{2} - CF}{f} \right) \times w

    First, find the median class. N/2=68/2=34N/2 = 68/2 = 34. The 34th value falls in the class 6-10 (since its cumulative frequency is 42, which is the first CFCF greater than or equal to 34).

    • LL (lower boundary of median class) = 6−0.5=5.56 - 0.5 = 5.5
    • CFCF (cumulative frequency of class before median class) = 12 (for class 1-5)
    • ff (frequency of median class) = 30
    • ww (class width) = 10.5−5.5=510.5 - 5.5 = 5

    Substitute these values into the formula:

    Median=5.5+(34−1230)×5\text{Median} = 5.5 + \left( \frac{34 - 12}{30} \right) \times 5 Median=5.5+(2230)×5\text{Median} = 5.5 + \left( \frac{22}{30} \right) \times 5 Median=5.5+11030\text{Median} = 5.5 + \frac{110}{30} Median=5.5+3.666...\text{Median} = 5.5 + 3.666...

    Rounding to two decimal places, the median is 9.17\boxed{\text{9.17}}.

  4. Calculate the Mode.

    The formula for the mode of grouped data is:

    Mode=L+(fm−f1(fm−f1)+(fm−f2))×w\text{Mode} = L + \left( \frac{f_m - f_1}{(f_m - f_1) + (f_m - f_2)} \right) \times w

    First, identify the modal class (the class with the highest frequency). The highest frequency is 30, which corresponds to the class 6-10.

    • LL (lower boundary of modal class) = 6−0.5=5.56 - 0.5 = 5.5
    • fmf_m (frequency of modal class) = 30
    • f1f_1 (frequency of class before modal class) = 12 (for class 1-5)
    • f2f_2 (frequency of class after modal class) = 9 (for class 11-15)
    • ww (class width) = 10.5−5.5=510.5 - 5.5 = 5

    Substitute these values into the formula:

    Mode=5.5+(30−12(30−12)+(30−9))×5\text{Mode} = 5.5 + \left( \frac{30 - 12}{(30 - 12) + (30 - 9)} \right) \times 5 Mode=5.5+(1818+21)×5\text{Mode} = 5.5 + \left( \frac{18}{18 + 21} \right) \times 5 Mode=5.5+(1839)×5\text{Mode} = 5.5 + \left( \frac{18}{39} \right) \times 5 Mode=5.5+9039\text{Mode} = 5.5 + \frac{90}{39} Mode=5.5+2.307...\text{Mode} = 5.5 + 2.307...

    Rounding to two decimal places, the mode is 7.81\boxed{\text{7.81}}.

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