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Determine how much pocket money will each child get. Determine the amount paid for a child in the; first installment, second installment. When is he likely to have a meeting and a follow up visit at the same time?

Mathematics

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Item 1:

Part a· 3 steps

Determine how much pocket money each child will get.

  1. Calculate the total sum of the children's ages.

    The ages are 5, 10, 12, and 13 years.

    Sum of ages=5+10+12+13=40\text{Sum of ages} = 5 + 10 + 12 + 13 = 40
  2. Calculate the value of one ratio part.

    The total pocket money is Shs 520,000.

    Value per ratio part=Total pocket moneySum of ages=520,00040=13,000 Shs\text{Value per ratio part} = \frac{\text{Total pocket money}}{\text{Sum of ages}} = \frac{520,000}{40} = 13,000 \text{ Shs}
  3. Calculate the pocket money for each child.

    • Child 1 (5 years old): 5×13,000=65,000 Shs5 \times 13,000 = \boxed{\text{65,000 Shs}}
    • Child 2 (10 years old): 10×13,000=130,000 Shs10 \times 13,000 = \boxed{\text{130,000 Shs}}
    • Child 3 (12 years old): 12×13,000=156,000 Shs12 \times 13,000 = \boxed{\text{156,000 Shs}}
    • Child 4 (13 years old): 13×13,000=169,000 Shs13 \times 13,000 = \boxed{\text{169,000 Shs}}

Part b(i)

first installment

Determine the amount paid for a child in the

Part b(ii)· 4 steps

second installment

  1. Let TT be the total school fees for a child.

    Set up an equation based on the installment payments.

    • First installment = 60%60\% of T=0.60TT = 0.60T
    • Remaining amount after first installment = T−0.60T=0.40TT - 0.60T = 0.40T
    • Second installment = 23\frac{2}{3} of the remaining amount = 23×0.40T=0.803T\frac{2}{3} \times 0.40T = \frac{0.80}{3}T
    • Third installment = Shs 160,000 The sum of the installments equals the total fees:
    T=0.60T+0.803T+160,000T = 0.60T + \frac{0.80}{3}T + 160,000
  2. Solve the equation for TT.

    T−0.60T−0.803T=160,000T - 0.60T - \frac{0.80}{3}T = 160,000 0.40T−0.803T=160,0000.40T - \frac{0.80}{3}T = 160,000

    Multiply by 3 to clear the fraction:

    3×0.40T−0.80T=3×160,0003 \times 0.40T - 0.80T = 3 \times 160,000 1.20T−0.80T=480,0001.20T - 0.80T = 480,000 0.40T=480,0000.40T = 480,000 T=480,0000.40=1,200,000 ShsT = \frac{480,000}{0.40} = 1,200,000 \text{ Shs}

    The total school fees for a child is Shs 1,200,000.

  3. Calculate the first installment.

    First installment=0.60×1,200,000=720,000 Shs\text{First installment} = 0.60 \times 1,200,000 = \boxed{\text{720,000 Shs}}
  4. Calculate the second installment.

    Remaining amount=1,200,000−720,000=480,000 Shs\text{Remaining amount} = 1,200,000 - 720,000 = 480,000 \text{ Shs} Second installment=23×480,000=320,000 Shs\text{Second installment} = \frac{2}{3} \times 480,000 = \boxed{\text{320,000 Shs}}

Part c· 3 steps

When is he likely to have a meeting and a follow up visit at the same time?

  1. Determine the frequency of each event.

    • Follow-up visits occur every 21 days.
    • Weekly meetings occur every 7 days.
  2. Find the least common multiple (LCM) of the frequencies to determine when they coincide.

    LCM(21,7)=21 days\text{LCM}(21, 7) = 21 \text{ days}

    This means both events will coincide every 21 days.

  3. Calculate the next date of coincidence.

    The last coincidence was on 11/05/2025. Add 21 days to this date.
    May has 31 days.
    11 (May)+21 days=32 days into May11 \text{ (May)} + 21 \text{ days} = 32 \text{ days into May}
    Since May has 31 days, 32−31=132 - 31 = 1.
    The next coincidence will be on 01/06/2025\boxed{\text{01/06/2025}}.

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