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Calculate how much was deposited into her bank account.

Mathematics

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5 parts
1.6

R2 000\text{R}2\,000

1.7

R10 800\text{R}10\,800

1.8

R1 700\text{R}1\,700

1.9

R880\text{R}880

1.10

R12 150\text{R}12\,150

Step-by-step solution

12 steps

Here are the solutions to the questions:

Part 1.4

The invoice itself is not provided in the image. Therefore, I cannot identify the job title and company name to which it is addressed.

Part 1.5

Pamela's fixed income each month is her basic salary. Her fixed income is R8 000.

Part 1.6

R2 000\text{R}2\,000

  1. Identify the hours worked and the hourly rate for electrical work.

    Pamela worked 4 hours and earns R500 per hour.

  2. Calculate the total earnings for electrical work (P).

    P=Hours worked×Hourly rateP = \text{Hours worked} \times \text{Hourly rate} P=4 hours×R500/hourP = 4 \text{ hours} \times \text{R}500/\text{hour} P=R2 000P = \text{R}2\,000

    The value of P is R2 000\boxed{\text{R}2\,000}.

Part 1.7

R10 800\text{R}10\,800

  1. Calculate the total number of graphic designs completed.

    Total designs=Macro Ends+Fish Den+Intensity investments\text{Total designs} = \text{Macro Ends} + \text{Fish Den} + \text{Intensity investments} Total designs=3+2+1\text{Total designs} = 3 + 2 + 1 Total designs=6\text{Total designs} = 6

  2. Calculate the total income from graphic design work (Q).

    Pamela earns R1 800 per design.

    Q=Total designs×Payment per designQ = \text{Total designs} \times \text{Payment per design} Q=6×R1 800Q = 6 \times \text{R}1\,800 Q=R10 800Q = \text{R}10\,800

    The value of Q is R10 800\boxed{\text{R}10\,800}.

Part 1.8

R1 700\text{R}1\,700

  1. Calculate the UIF contribution.

    Total income = R20 000.
    UIF contribution = 1% of total income.

    UIF=0.01×R20 000\text{UIF} = 0.01 \times \text{R}20\,000 UIF=R200\text{UIF} = \text{R}200

  2. Calculate the pension fund contribution.

    Pension contribution = 7.5% of total income.

    Pension=0.075×R20 000\text{Pension} = 0.075 \times \text{R}20\,000 Pension=R1 500\text{Pension} = \text{R}1\,500

  3. Calculate the total combined contribution to UIF and Pension.

    Total contribution=UIF+Pension\text{Total contribution} = \text{UIF} + \text{Pension} Total contribution=R200+R1 500\text{Total contribution} = \text{R}200 + \text{R}1\,500 Total contribution=R1 700\text{Total contribution} = \text{R}1\,700

    The total she contributes to UIF and Pension combined is R1 700\boxed{\text{R}1\,700}.

Part 1.9

R880\text{R}880

  1. Identify the number of people covered by the R2 640 contribution.

    The R2 640 covers her mother and two children.

    Number of people=1(mother)+2(children)=3 people\text{Number of people} = 1 (\text{mother}) + 2 (\text{children}) = 3 \text{ people}

  2. Calculate the amount paid per person for this group.

    Cost per person=Total contributionNumber of people\text{Cost per person} = \frac{\text{Total contribution}}{\text{Number of people}} Cost per person=R2 6403\text{Cost per person} = \frac{\text{R}2\,640}{3} Cost per person=R880\text{Cost per person} = \text{R}880

    She pays R880\boxed{\text{R}880} per person for her mother and two children.

Part 1.10

R12 150\text{R}12\,150

  1. List all contributions/deductions.

    • UIF: R200
    • Pension: R1 500
    • Medical aid (mother and children): R2 640
    • Medical aid (own): R510
    • Tax: R3 000

  2. Calculate the total deductions.

    Total deductions=R200+R1 500+R2 640+R510+R3 000\text{Total deductions} = \text{R}200 + \text{R}1\,500 + \text{R}2\,640 + \text{R}510 + \text{R}3\,000 Total deductions=R7 850\text{Total deductions} = \text{R}7\,850

  3. Calculate the amount deposited into her bank account (net income).

    Total income = R20 000.

    Amount deposited=Total income−Total deductions\text{Amount deposited} = \text{Total income} - \text{Total deductions} Amount deposited=R20 000−R7 850\text{Amount deposited} = \text{R}20\,000 - \text{R}7\,850 Amount deposited=R12 150\text{Amount deposited} = \text{R}12\,150

    The amount deposited into her bank account is R12 150\boxed{\text{R}12\,150}.

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