This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
You're on a roll — To make $k$ the subject of the formula $r = \frac{2v+4}{\sqrt{2kv+k}}$ and simplify, we need to isolate $k$.
Step 1: Multiply both sides by $\sqrt{2kv+k}$.
$$ r\sqrt{2kv+k} = 2v+4 $$
Step 2: Square both sides to eliminate the square root.
$$ (r\sqrt{2kv+k})^2 = (2v+4)^2 $$
$$ r^2(2kv+k) = (2v+4)^2 $$
Step 3: Expand the left side and factor out $k$.
$$ 2kvr^2 + kr^2 = (2v+4)^2 $$
$$ k(2vr^2 + r^2) = (2v+4)^2 $$
Step 4: Isolate $k$ by dividing both sides by $(2vr^2 + r^2)$.
$$ k = \frac{(2v+4)^2}{2vr^2 + r^2} $$
Step 5: Simplify the denominator by factoring out $r^2$.
$$ k = \frac{(2v+4)^2}{r^2(2v+1)} $$
The expression for $k$ is:
$$ \boxed{k = \frac{(2v+4)^2}{r^2(2v+1)}} $$
4 down, 1 left today. What's next?
Multiply both sides by sqrt(2kv+k).
|Mathematics
Multiply both sides by sqrt(2kv+k).
ScanSolve AI Answer
You're on a roll — To make k the subject of the formula r=2kv+k2v+4 and simplify, we need to isolate k.
Step 1: Multiply both sides by 2kv+k.
r2kv+k=2v+4
Step 2: Square both sides to eliminate the square root.
(r2kv+k)2=(2v+4)2r2(2kv+k)=(2v+4)2
Step 3: Expand the left side and factor out k.
2kvr2+kr2=(2v+4)2k(2vr2+r2)=(2v+4)2
Step 4: Isolate k by dividing both sides by (2vr2+r2).
k=2vr2+r2(2v+4)2
Step 5: Simplify the denominator by factoring out r2.
k=r2(2v+1)(2v+4)2
The expression for k is:
k = \frac{(2v+4)^2{r^2(2v+1)}}
4 down, 1 left today. What's next?
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