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Multiply the binomials: (2x+5) and (4x-3); (y-8) and (3y-4); (2.5l - 0.5m) and (2.5l + 0.5m); (a+3b) and (x+5); (2pq+3q2) and (3pq-2q2).

Mathematics

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17 steps

Here are the solutions for the 1st question:

1. Multiply the binomials.

  • 1 (i): (2x+5)(2x+5) and (4x−3)(4x-3)
  1. Use the distributive property (FOIL method).

    $$
    (2x+5)(4x-3) = 2x(4x) + 2x(-3) + 5(4x) + 5(-3)
    $$
    
  2. Perform the multiplications.

    $$
    = 8x^2 - 6x + 20x - 15
    $$
    
  3. Combine like terms.

    $$
    = \boxed{8x^2 + 14x - 15}
    $$
    
    • 1 (ii): (y−8)(y-8) and (3y−4)(3y-4)
  4. Use the distributive property (FOIL method).

    $$
    (y-8)(3y-4) = y(3y) + y(-4) - 8(3y) - 8(-4)
    $$
    
  5. Perform the multiplications.

    $$
    = 3y^2 - 4y - 24y + 32
    $$
    
  6. Combine like terms.

    $$
    = \boxed{3y^2 - 28y + 32}
    $$
    
    • 1 (iii): (2.5l−0.5m)(2.5l - 0.5m) and (2.5l+0.5m)(2.5l + 0.5m)
  7. Recognize this as a difference of squares

    (A−B)(A+B)=A2−B2(A-B)(A+B) = A^2 - B^2. Here A=2.5lA=2.5l and B=0.5mB=0.5m. (2.5l−0.5m)(2.5l+0.5m)=(2.5l)2−(0.5m)2 (2.5l - 0.5m)(2.5l + 0.5m) = (2.5l)^2 - (0.5m)^2

  8. Square each term.

    $$
    = (2.5)^2 l^2 - (0.5)^2 m^2
    $$
    $$
    = \boxed{6.25l^2 - 0.25m^2}
    $$
    
    • 1 (iv): (a+3b)(a+3b) and (x+5)(x+5)
  9. Use the distributive property (FOIL method).

    $$
    (a+3b)(x+5) = a(x) + a(5) + 3b(x) + 3b(5)
    $$
    
  10. Perform the multiplications.

    $$
    = \boxed{ax + 5a + 3bx + 15b}
    $$
    
    • 1 (v): (2pq+3q2)(2pq+3q^2) and (3pq−2q2)(3pq-2q^2)
  11. Use the distributive property (FOIL method).

    $$
    (2pq+3q^2)(3pq-2q^2) = 2pq(3pq) + 2pq(-2q^2) + 3q^2(3pq) + 3q^2(-2q^2)
    $$
    
  12. Perform the multiplications.

    $$
    = 6p^2q^2 - 4pq^3 + 9pq^3 - 6q^4
    $$
    
  13. Combine like terms.

    $$
    = \boxed{6p^2q^2 + 5pq^3 - 6q^4}
    $$
    
    • 1 (vi): (34a2+3b2)(\frac{3}{4}a^2+3b^2) and 4(a2−23b2)4(a^2-\frac{2}{3}b^2)
  14. Distribute the 4 into the second expression.

    $$
    4(a^2-\frac{2}{3}b^2) = 4a^2 - 4 \times \frac{2}{3}b^2 = 4a^2 - \frac{8}{3}b^2
    $$
    
  15. Multiply the two binomials

    (34a2+3b2)(4a2−83b2)(\frac{3}{4}a^2+3b^2)(4a^2-\frac{8}{3}b^2). =34a2(4a2)+34a2(−83b2)+3b2(4a2)+3b2(−83b2) = \frac{3}{4}a^2(4a^2) + \frac{3}{4}a^2(-\frac{8}{3}b^2) + 3b^2(4a^2) + 3b^2(-\frac{8}{3}b^2)

  16. Perform the multiplications.

    $$
    = 3a^4 - \frac{24}{12}a^2b^2 + 12a^2b^2 - \frac{24}{3}b^4
    $$
    
  17. Simplify the fractions and combine like terms.

    $$
    = 3a^4 - 2a^2b^2 + 12a^2b^2 - 8b^4
    $$
    $$
    = \boxed{3a^4 + 10a^2b^2 - 8b^4}
    $$
    
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