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Name the property used in each of the following: a) 3/8 + 5/12 = 5/12 + 3/8 b) -5/8 + 0 = -5/8 c) -3/11 + 3/11 = 0 d) -5/4 * 4/-5 = 1

Mathematics

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6. Name the property used in each of the following.

Part a

38+512=512+38\frac{3}{8} + \frac{5}{12} = \frac{5}{12} + \frac{3}{8}

This is the **Commutative Property of Addition**.

Part b

−58+0=−58\frac{-5}{8} + 0 = \frac{-5}{8}

This is the **Additive Identity Property**.

Part c

−311+311=0\frac{-3}{11} + \frac{3}{11} = 0

This is the **Additive Inverse Property**.

Part d· 5 steps

−54×4−5=1\frac{-5}{4} \times \frac{4}{-5} = 1

This is the **Multiplicative Inverse Property**.

7. Manish bought 2122 \frac{1}{2} kg potatoes and 3143 \frac{1}{4} kg onions. How many kg of vegetables did he buy?

  1. Convert mixed numbers to improper fractions.

    Potatoes: 212=(2×2)+12=522 \frac{1}{2} = \frac{(2 \times 2) + 1}{2} = \frac{5}{2} kg
    Onions: 314=(3×4)+14=1343 \frac{1}{4} = \frac{(3 \times 4) + 1}{4} = \frac{13}{4} kg

  2. Add the quantities.

    Total vegetables = 52+134\frac{5}{2} + \frac{13}{4}
    Find a common denominator, which is 4.
    52=5×22×2=104\frac{5}{2} = \frac{5 \times 2}{2 \times 2} = \frac{10}{4}
    Total vegetables = 104+134=10+134=234\frac{10}{4} + \frac{13}{4} = \frac{10+13}{4} = \frac{23}{4} kg

  3. Convert the improper fraction back to a mixed number.

    234=534\frac{23}{4} = 5 \frac{3}{4} kg

    Manish bought \boxed{\text{5 \frac{3}{4} kg}} of vegetables.

    8. The sides of a triangular field are 4124 \frac{1}{2} cm, 4344 \frac{3}{4} cm and 5185 \frac{1}{8} cm. Find its perimeter.

  4. Convert mixed numbers to improper fractions.

    Side 1: 412=(4×2)+12=924 \frac{1}{2} = \frac{(4 \times 2) + 1}{2} = \frac{9}{2} cm
    Side 2: 434=(4×4)+34=1944 \frac{3}{4} = \frac{(4 \times 4) + 3}{4} = \frac{19}{4} cm
    Side 3: 518=(5×8)+18=4185 \frac{1}{8} = \frac{(5 \times 8) + 1}{8} = \frac{41}{8} cm

  5. Add the lengths of the sides to find the perimeter.

    Perimeter = 92+194+418\frac{9}{2} + \frac{19}{4} + \frac{41}{8}
    Find a common denominator, which is the LCM of 2, 4, and 8, which is 8.
    92=9×42×4=368\frac{9}{2} = \frac{9 \times 4}{2 \times 4} = \frac{36}{8}
    194=19×24×2=388\frac{19}{4} = \frac{19 \times 2}{4 \times 2} = \frac{38}{8}
    Perimeter = 368+388+418=36+38+418=1158\frac{36}{8} + \frac{38}{8} + \frac{41}{8} = \frac{36+38+41}{8} = \frac{115}{8} cm

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