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Home > Mathematics Homework Help > Solution

No the question was a division ⅗÷12/7

Asked on March 28, 2026|Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on March 28, 2026
You are correct. My apologies for the error. Let's re-solve 4. a) with division. 4. a) Step 1: Rewrite the division of fractions as multiplication by the reciprocal of the second fraction. $$\frac{3}{5} \div \frac{12}{7} = \frac{3}{5} \times \frac{7}{12}$$ Step 2: Multiply the numerators and multiply the denominators. $$\frac{3 \times 7}{5 \times 12} = \frac{21}{60}$$ Step 3: Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor. The greatest common divisor of 21 and 60 is 3. $$\frac{21 \div 3}{60 \div 3} = \frac{7}{20}$$ The simplified expression is $\boxed{\frac{7}{20}}$.

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Home›Mathematics Homework Help›No the question was a division ⅗÷12/7
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No the question was a division ⅗÷12/7

March 28, 2026|Mathematics
ScanSolve AI

ScanSolve AI Answer

Answered on March 28, 2026

You are correct. My apologies for the error. Let's re-solve 4. a) with division.

4. a) Step 1: Rewrite the division of fractions as multiplication by the reciprocal of the second fraction. 35÷127=35×712\frac{3}{5} \div \frac{12}{7} = \frac{3}{5} \times \frac{7}{12}53​÷712​=53​×127​ Step 2: Multiply the numerators and multiply the denominators. 3×75×12=2160\frac{3 \times 7}{5 \times 12} = \frac{21}{60}5×123×7​=6021​ Step 3: Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor. The greatest common divisor of 21 and 60 is 3. 21÷360÷3=720\frac{21 \div 3}{60 \div 3} = \frac{7}{20}60÷321÷3​=207​

The simplified expression is 720\boxed{\frac{7}{20}}207​​.

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Set up the partial fraction decomposition.Convert the percentage abundances to fractional abundances.What is the Pythagorean theorem?1. Find the degree of each polynomialDifferentiate each term using the power rule (d)/(dx)(ax^n) = anx^n-1 and the rule for constants (d)…Solve number 5-7 na please
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Mathematics: No the question was a division ⅗÷12/7 — Step-by-Step Solution | ScanSolve