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Now do these: (1) 3 3/8 (2) 2 2/3 (3) 3 3/4 (4) 3 3/4

Mathematics

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Okay, nwekechidubem247. I see the image again. My apologies for the confusion in the previous response regarding the problem number. The problem I solved previously, 414−2124\frac{1}{4} - 2\frac{1}{2}, was a problem with handwritten work on the page, not one of the numbered problems (1) through (4) in the "Now do these" section.

Let's solve problem (1) from the "Now do these" section: 338−233\frac{3}{8} - \frac{2}{3}.

  1. Convert the mixed number to an improper fraction.

    338=(3×8)+38=24+38=2783\frac{3}{8} = \frac{(3 \times 8) + 3}{8} = \frac{24 + 3}{8} = \frac{27}{8}
  2. Find a common denominator for the fractions 278\frac{27}{8} and 23\frac{2}{3}.

    The least common multiple (LCM) of 8 and 3 is 24.

  3. Convert both fractions to equivalent fractions with the common denominator.

    278=27×38×3=8124\frac{27}{8} = \frac{27 \times 3}{8 \times 3} = \frac{81}{24} 23=2×83×8=1624\frac{2}{3} = \frac{2 \times 8}{3 \times 8} = \frac{16}{24}
  4. Subtract the fractions.

    8124−1624=81−1624=6524\frac{81}{24} - \frac{16}{24} = \frac{81 - 16}{24} = \frac{65}{24}
  5. Convert the improper fraction back to a mixed number.

    65÷24=2 with a remainder of 65−(2×24)=65−48=1765 \div 24 = 2 \text{ with a remainder of } 65 - (2 \times 24) = 65 - 48 = 17

    So, the result is 217242\frac{17}{24}.

    The final answer is 21724\boxed{2\frac{17}{24}}.

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