Evaluate the numerator.

Step 1: Evaluate the numerator. 8-2+12 × 9-4 × 6 Perform multiplications first: 8-2+108-24 Perform additions and subtractions from left to right: 6+108-24 114-24 90 The numerator is 90. Step 2: Evaluate the denominator. 56 ÷ 7(2) Perform division first: 8(2) Perform multiplication: 16 The denominator is 16. Step 3: Divide the numerator by the denominator. (90)/(16) Simplify the fraction by dividing both numerator and denominator by their greatest common divisor, which is 2: (90 ÷ 2)/(16 ÷ 2) = (45)/(8) The fraction can also be expressed as a mixed number: 5(5)/(8) The question asks to evaluate, so the simplified fraction is acceptable. The final answer is (45)/(8). Step 1: Find the greatest common divisor (GCD) of the dimensions of the land. The dimensions are 840 m and 396 m. The side length of the largest possible square plot will be the GCD of these two numbers. Using prime factorization: 840 = 2^3 × 3 × 5 × 7 396 = 2^2 × 3^2 × 11 The GCD is the product of the lowest powers of common prime factors: GCD(840, 396) = 2^2 × 3 = 4 × 3 = 12 So, the side length of each square plot is 12 m. Step 2: Calculate the number of plots along each dimension. Number of plots along the 840 m side: 840 m12 m/plot = 70 plots Number of plots along the 396 m side: 396 m12 m/plot = 33 plots Step 3: Calculate the total number of plots. Total number of plots = (plots along length) × (plots along width) 70 × 33 = 2310 The final answer is 2310. Step 1: Identify the relevant formula for the circumradius. The distance OS is the radius (R) of the circumcircle. According to the sine rule, for any triangle with sides a, b, c and opposite angles A, B, C, the following relationship holds: (a)/( A) = (b)/( B) = (c)/( C) = 2R In triangle RSQ, we are given side QR = 12 cm and its opposite angle RSQ = 50^. Step 2: Substitute the given values into the sine rule to find R. (QR)/(( RSQ)) = 2R 12 cm(50^) = 2R Solve for R: R = 12 cm2 (50^) R = 6 cm(50^) Step 3: Calculate the value of R and round to 2 decimal places. Using a calculator for (50^): (50^) ≈ 0.76604444 Now, calculate R: R = (6)/(0.76604444) ≈ 7.832409 cm Rounding to 2 decimal places: R ≈ 7.83 cm The distance OS is R. The final answer is 7.83 cm.