Example: What happens when we start adding up odd numbers? 1=1, 1+3=4

Mathematics
Example: What happens when we start adding up odd numbers? 1=1, 1+3=4

ScanSolve AI Answer

Answer

32

Step 1: Observe the recursive construction from the diagrams.
Each higher-dimensional figure is built by taking two copies of the previous figure and connecting corresponding dots with edges.

The number of vertices VnV_n in the nn-dimensional figure satisfies:
V0=1V_0 = 1
Vn=2Vn1forn1V_n = 2 \cdot V_{n-1} \quad for \quad n \geq 1

Step 2: Verify with given diagrams.
For n=1n=1: V1=2V0=21=2V_1 = 2 \cdot V_0 = 2 \cdot 1 = 2
For n=2n=2: V2=2V1=22=4V_2 = 2 \cdot V_1 = 2 \cdot 2 = 4
For n=3n=3: V3=2V2=24=8V_3 = 2 \cdot V_2 = 2 \cdot 4 = 8
For n=4n=4: V4=2V3=28=16V_4 = 2 \cdot V_3 = 2 \cdot 8 = 16

Step 3: Solve the recurrence relation.
Unrolling the recursion:
Vn=2Vn1=22Vn2==2nV0=2n1=2nV_n = 2 \cdot V_{n-1} = 2^2 \cdot V_{n-2} = \cdots = 2^n \cdot V_0 = 2^n \cdot 1 = 2^n

Step 4: This matches the powers of 2 and the number of binary sequences of length nn (each dot labels a sequence of 00s and 11s).

For the 5-dimensional figure, the number of vertices is V5=25V_5 = 2^5.
25=322^5 = 32

32

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Quick Answer

Observe the recursive construction from the diagrams. Each higher-dimensional figure is built by taking two copies of the previous figure and connecting corresponding dots with edges.

Example: What happens when we start adding up odd numbers? 1=1, 1+3=4
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Step 1: Observe the recursive construction from the diagrams. Each higher-dimensional figure is built by taking two copies of the previous figure and connecting corresponding dots with edges. The number of vertices V_n in the n-dimensional figure satisfies: V_0 = 1 V_n = 2 · V_n-1 for n ≥ 1 Step 2: Verify with given diagrams. For n=1: V_1 = 2 · V_0 = 2 · 1 = 2 For n=2: V_2 = 2 · V_1 = 2 · 2 = 4 For n=3: V_3 = 2 · V_2 = 2 · 4 = 8 For n=4: V_4 = 2 · V_3 = 2 · 8 = 16 Step 3: Solve the recurrence relation. Unrolling the recursion: V_n = 2 · V_n-1 = 2^2 · V_n-2 = ·s = 2^n · V_0 = 2^n · 1 = 2^n Step 4: This matches the powers of 2 and the number of binary sequences of length n (each dot labels a sequence of 0s and 1s). For the 5-dimensional figure, the number of vertices is V_5 = 2^5. 2^5 = 32 32