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Example: What happens when we start adding up odd numbers? 1=1, 1+3=4

Mathematics

ScanSolve AI Answer

Answer

32

Step-by-step solution

4 steps
  1. Observe the recursive construction from the diagrams.

    Each higher-dimensional figure is built by taking two copies of the previous figure and connecting corresponding dots with edges.

    The number of vertices VnV_n in the nn-dimensional figure satisfies:

    V0=1V_0 = 1 Vn=2⋅Vn−1forn≥1V_n = 2 \cdot V_{n-1} \quad \text{for} \quad n \geq 1
  2. Verify with given diagrams.

    For n=1n=1: V1=2⋅V0=2⋅1=2V_1 = 2 \cdot V_0 = 2 \cdot 1 = 2
    For n=2n=2: V2=2⋅V1=2⋅2=4V_2 = 2 \cdot V_1 = 2 \cdot 2 = 4
    For n=3n=3: V3=2⋅V2=2⋅4=8V_3 = 2 \cdot V_2 = 2 \cdot 4 = 8
    For n=4n=4: V4=2⋅V3=2⋅8=16V_4 = 2 \cdot V_3 = 2 \cdot 8 = 16

  3. Solve the recurrence relation.

    Unrolling the recursion:

    Vn=2⋅Vn−1=22⋅Vn−2=⋯=2n⋅V0=2n⋅1=2nV_n = 2 \cdot V_{n-1} = 2^2 \cdot V_{n-2} = \cdots = 2^n \cdot V_0 = 2^n \cdot 1 = 2^n
  4. This matches the powers of 2 and the number of binary sequences of length nn (each dot labels a sequence of 00s and 11s).

    For the 5-dimensional figure, the number of vertices is V5=25V_5 = 2^5.

    25=322^5 = 32

    32

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