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Which of these years was a leap year: 2020, 2021, 2022?

Mathematics

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Here are the solutions for questions one to twelve:

1) Numbers can either be written in figures, words or Roman numerals. Write in figures: One and a half million

  1. One million is 1,000,000.

  2. Half a million is 500,000.

  3. Add these values.

    1,000,000+500,000=1,500,0001,000,000 + 500,000 = 1,500,000

    In figures, one and a half million is 1,500,000\boxed{1,500,000}.

    2) Fractions can be expressed as decimals. Express % as a decimal
    To express a percentage as a decimal, divide the percentage value by 100.
    For example, X%X\% is equivalent to X100\frac{X}{100} as a decimal.
    So, to express a percentage as a decimal, you divide the number by 100. For example, 25%=25100=0.2525\% = \frac{25}{100} = \boxed{0.25}.

    3) Numbers written in index form can be expanded. Expand 72×537^2 \times 5^3

  4. Expand 727^2.

    72=7×7=497^2 = 7 \times 7 = 49
  5. Expand 535^3.

    53=5×5×5=1255^3 = 5 \times 5 \times 5 = 125
  6. Multiply the expanded values.

    49×125=612549 \times 125 = 6125

    The expanded form is 49×125=6125\boxed{49 \times 125 = 6125}.

    4) Some years are called leap years. Which of these years was a leap year: 2020, 2021, 2022?

  7. A leap year is generally divisible by 4.

  8. Check each year

    • 2020÷4=5052020 \div 4 = 505. 2020 is divisible by 4, so it is a leap year.
    • 2021÷4=5052021 \div 4 = 505 with a remainder of 1. Not a leap year.
    • 2022÷4=5052022 \div 4 = 505 with a remainder of 2. Not a leap year. The leap year among the given years is 2020\boxed{2020}.

    5) A mixed fraction can be converted to an improper fraction. Convert 141214 \frac{1}{2} to an improper fraction.

  9. Multiply the whole number by the denominator.

    14×2=2814 \times 2 = 28
  10. Add the numerator to the result.

    28+1=2928 + 1 = 29
  11. Place this sum over the original denominator.

    The improper fraction is 292\boxed{\frac{29}{2}}.

    6) Write 16.53675 correct to 4 significant figures.

  12. Identify the first four significant figures

    1, 6, 5, 3.

  13. Look at the fifth significant figure, which is 6.

  14. Since 6 is 5 or greater, round up the fourth significant figure (3).

    The number becomes 16.54.
    16.53675 correct to 4 significant figures is 16.54\boxed{16.54}.

    7) Given that x=5x = 5 and y=4y = 4, calculate (x+y)2÷(2x−y)2(x+y)^2 \div (2x-y)^2

  15. Substitute x=5x=5 and y=4y=4 into the first part of the expression.

    (x+y)2=(5+4)2=92=81(x+y)^2 = (5+4)^2 = 9^2 = 81
  16. Substitute x=5x=5 and y=4y=4 into the second part of the expression.

    (2x−y)2=(2×5−4)2=(10−4)2=62=36(2x-y)^2 = (2 \times 5 - 4)^2 = (10 - 4)^2 = 6^2 = 36
  17. Perform the division.

    (x+y)2÷(2x−y)2=81÷36(x+y)^2 \div (2x-y)^2 = 81 \div 36 8136=9×94×9=94\frac{81}{36} = \frac{9 \times 9}{4 \times 9} = \frac{9}{4}

    As a decimal, 94=2.25\frac{9}{4} = 2.25.
    The value of the expression is 94 or 2.25\boxed{\frac{9}{4} \text{ or } 2.25}.

    8) The sum of two numbers is 502. If one of the numbers is 128, what is the value of the other number?

  18. Let the other number be NN.

  19. Set up the equation.

    128+N=502128 + N = 502
  20. Solve for NN.

    N=502−128N = 502 - 128 N=374N = 374

    The value of the other number is 374\boxed{374}.

    9) Modular arithmetic deals with the remainder. What is 3+7(mod4)3 + 7 \pmod{4}?

  21. Perform the addition.

    3+7=103 + 7 = 10
  22. Find the remainder when 10 is divided by 4.

    10÷4=2 with a remainder of 210 \div 4 = 2 \text{ with a remainder of } 2

    So, 3+7(mod4)3 + 7 \pmod{4} is 2\boxed{2}.

    10) A clock loses 2 minutes in every 3 hours. How many minutes does it lose in 15 hours?

  23. Determine the rate of loss per hour.

    Rate of loss=2 minutes3 hours\text{Rate of loss} = \frac{2 \text{ minutes}}{3 \text{ hours}}
  24. Multiply the rate by the total hours.

    Total loss=23 minutes/hour×15 hours\text{Total loss} = \frac{2}{3} \text{ minutes/hour} \times 15 \text{ hours} Total loss=2×153 minutes\text{Total loss} = \frac{2 \times 15}{3} \text{ minutes} Total loss=303 minutes\text{Total loss} = \frac{30}{3} \text{ minutes} Total loss=10 minutes\text{Total loss} = 10 \text{ minutes}

    The clock loses 10 minutes\boxed{10 \text{ minutes}} in 15 hours.

    11) After spending 14\frac{1}{4} of my money on bread and 13\frac{1}{3} on eggs, what fraction have I left?

  25. Find the total fraction of money spent.

    Total spent=14+13\text{Total spent} = \frac{1}{4} + \frac{1}{3}
  26. Find a common denominator, which is 12.

    14=312\frac{1}{4} = \frac{3}{12} 13=412\frac{1}{3} = \frac{4}{12}
  27. Add the fractions.

    Total spent=312+412=712\text{Total spent} = \frac{3}{12} + \frac{4}{12} = \frac{7}{12}
  28. Subtract the spent fraction from the total (1, or 1212\frac{12}{12}).

    Fraction left=1−712=1212−712=512\text{Fraction left} = 1 - \frac{7}{12} = \frac{12}{12} - \frac{7}{12} = \frac{5}{12}

    The fraction of money left is 512\boxed{\frac{5}{12}}.

    12) If ξ={1,2,3,4,5,6,...,10}\xi = \{1, 2, 3, 4, 5, 6, ..., 10\}, A={1,3,6,9,10}A = \{1, 3, 6, 9, 10\} and B={2,4,6,8,10}B = \{2, 4, 6, 8, 10\}, Find (A∩B)′(A \cap B)'

  29. List the universal set ξ\xi.

    ξ={1,2,3,4,5,6,7,8,9,10}\xi = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}
  30. Find the intersection of sets A and B (A∩BA \cap B), which are the elements common to both sets.

    A={1,3,6,9,10}A = \{1, 3, 6, 9, 10\} B={2,4,6,8,10}B = \{2, 4, 6, 8, 10\} A∩B={6,10}A \cap B = \{6, 10\}
  31. Find the complement of (A∩B)(A \cap B), denoted as (A∩B)′(A \cap B)'.

    This includes all elements in ξ\xi that are not in (A∩B)(A \cap B).

    (A∩B)′={1,2,3,4,5,7,8,9}(A \cap B)' = \{1, 2, 3, 4, 5, 7, 8, 9\}

    (A∩B)′={1,2,3,4,5,7,8,9}(A \cap B)' = \boxed{\{1, 2, 3, 4, 5, 7, 8, 9\}}.

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