Prepare a grouped frequency distribution table and compute the mean for the given religious education test scores.

Mathematics
Prepare a grouped frequency distribution table and compute the mean for the given religious education test scores.

ScanSolve AI Answer

Answer

12.97

Step 1: Order the data and determine class intervals. First, arrange the given scores in ascending order: 0, 4, 5, 6, 7, 8, 9, 9, 10, 10, 10, 11, 12, 12, 12, 13, 13, 14, 14, 15, 15, 16, 16, 17, 18, 19, 19, 20, 23, 24, 24

The total number of data points is n=31n = 31. The minimum value is 0 and the maximum value is 24. The range is 240=2424 - 0 = 24.

To determine the number of classes, we can use Sturges' formula: k=1+3.322log10(n)k = 1 + 3.322 \log_{10}(n). k=1+3.322log10(31)1+3.322×1.4911+4.9565.956k = 1 + 3.322 \log_{10}(31) \approx 1 + 3.322 \times 1.491 \approx 1 + 4.956 \approx 5.956 We can choose 5 or 6 classes. Let's choose 5 classes for a clear distribution. The class width (ww) is calculated as RangeNumberofclasses\frac{Range}{Number of classes}. w=245=4.8w = \frac{24}{5} = 4.8 We round up to 5 to ensure all data points are covered and to have convenient integer class limits.

The class intervals will be: 0-4 5-9 10-14 15-19 20-24

Step 2: Prepare the grouped frequency distribution table. For each class interval, we count the frequency (ff) of scores falling within it and calculate the midpoint (xx). The midpoint is the average of the lower and upper class limits. Then, we calculate the product fxf \cdot x.

| Class Interval | Tally | Frequency (ff) | Midpoint (xx) | fxf \cdot x | | :------------- | :---------------------------------- | :-------------- | :------------- | :---------- | | 0-4 | 0, 4 | 2 | 2 | 4 | | 5-9 | 5, 6, 7, 8, 9, 9 | 6 | 7 | 42 | | 10-14 | 10, 10, 10, 11, 12, 12, 12, 13, 13, 14, 14 | 11 | 12 | 132 | | 15-19 | 15, 15, 16, 16, 17, 18, 19, 19 | 8 | 17 | 136 | | 20-24 | 20, 23, 24, 24 | 4 | 22 | 88 | | Total | | 31 | | 402 |

Step 3: Compute the mean from the grouped frequency distribution table. The formula for the mean (xˉ\bar{x}) of grouped data is: xˉ=(fx)f\bar{x} = \frac{\sum (f \cdot x)}{\sum f} From the table, we have: (fx)=402\sum (f \cdot x) = 402 f=31\sum f = 31

Substitute these values into the formula: xˉ=40231\bar{x} = \frac{402}{31} xˉ12.9677419\bar{x} \approx 12.9677419 Rounding to two decimal places: xˉ12.97\bar{x} \approx 12.97

The grouped frequency distribution table is shown above. The computed mean is 12.97\boxed{*12.97*}.

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Quick Answer

Order the data and determine class intervals.

Prepare a grouped frequency distribution table and compute the mean for the given religious education test scores.
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Step 1: Order the data and determine class intervals. First, arrange the given scores in ascending order: 0, 4, 5, 6, 7, 8, 9, 9, 10, 10, 10, 11, 12, 12, 12, 13, 13, 14, 14, 15, 15, 16, 16, 17, 18, 19, 19, 20, 23, 24, 24 The total number of data points is n = 31. The minimum value is 0 and the maximum value is 24. The range is 24 - 0 = 24. To determine the number of classes, we can use Sturges' formula: k = 1 + 3.322 _10(n). k = 1 + 3.322 _10(31) ≈ 1 + 3.322 × 1.491 ≈ 1 + 4.956 ≈ 5.956 We can choose 5 or 6 classes. Let's choose 5 classes for a clear distribution. The class width (w) is calculated as RangeNumber of classes. w = (24)/(5) = 4.8 We round up to 5 to ensure all data points are covered and to have convenient integer class limits. The class intervals will be: 0-4 5-9 10-14 15-19 20-24 Step 2: Prepare the grouped frequency distribution table. For each class interval, we count the frequency (f) of scores falling within it and calculate the midpoint (x). The midpoint is the average of the lower and upper class limits. Then, we calculate the product f · x. | Class Interval | Tally | Frequency (f) | Midpoint (x) | f · x | | :------------- | :---------------------------------- | :-------------- | :------------- | :---------- | | 0-4 | 0, 4 | 2 | 2 | 4 | | 5-9 | 5, 6, 7, 8, 9, 9 | 6 | 7 | 42 | | 10-14 | 10, 10, 10, 11, 12, 12, 12, 13, 13, 14, 14 | 11 | 12 | 132 | | 15-19 | 15, 15, 16, 16, 17, 18, 19, 19 | 8 | 17 | 136 | | 20-24 | 20, 23, 24, 24 | 4 | 22 | 88 | | Total | | 31 | | 402 | Step 3: Compute the mean from the grouped frequency distribution table. The formula for the mean (x) of grouped data is: x = ( (f · x))/( f) From the table, we have: (f · x) = 402 f = 31 Substitute these values into the formula: x = (402)/(31) x ≈ 12.9677419 Rounding to two decimal places: x ≈ 12.97 The grouped frequency distribution table is shown above. The computed mean is 12.97.