Calculate the P6 parking costs for 12, 24, 36, and 48 hours, and for 26 hours.

Step 1: Complete the table for P6 (Question 1.1).
The formula for P6 parking cost is: Price for first 24 hours + (number of 12 hours $\times$ price for every 12 hours thereafter).
For P6:

• Price for first 24 hours: R85.00

• Price for every 12 hours thereafter: R42.00

• a) For 12 hours: This falls within the 0-24 hour bracket.

  $$P(12) = \text{R}85.00$$

• b) For 24 hours: This is exactly 24 hours.

  $$P(24) = \text{R}85.00$$

• c) For 36 hours: This is $24 \text{ hours} + 12 \text{ hours}$. Number of 12-hour blocks thereafter = $\frac{36 - 24}{12} = \frac{12}{12} = 1$.

  $$P(36) = \text{R}85.00 + (1 \times \text{R}42.00) = \text{R}85.00 + \text{R}42.00 = \text{R}127.00$$

• d) For 48 hours: This is $24 \text{ hours} + 24 \text{ hours}$. Number of 12-hour blocks thereafter = $\frac{48 - 24}{12} = \frac{24}{12} = 2$.

  $$P(48) = \text{R}85.00 + (2 \times \text{R}42.00) = \text{R}85.00 + \text{R}84.00 = \text{R}169.00$$

The completed table is:

(H) Number of hours	12 hours	24 hours	36 hours	48 hours
(P) Cost of parking	R85.00	R85.00	R127.00	R169.00

Step 2: Calculate the cost of parking at P6 for 26 hours (Question 1.2).

• First 24 hours: R85.00
• Remaining hours: $26 - 24 = 2$ hours.
• Since the rate is "per 12 hours or part thereof", 2 hours counts as one 12-hour block. Number of 12-hour blocks thereafter = $\lceil \frac{2}{12} \rceil = 1$. $$\text{Cost} = \text{R}85.00 + (1 \times \text{R}42.00) = \text{R}85.00 + \text{R}42.00 = \text{R}127.00$$ The cost of parking at P6 for 26 hours is $\boxed{\text{R}127.00}$.

Step 3: Answer questions about Parkade P7 (Questions 2.1 - 2.6).

• 2.1 How many hours are there in 3 full days?

  $$3 \text{ days} \times 24 \text{ hours/day} = 72 \text{ hours}$$

  There are $\boxed{72 \text{ hours}}$ in 3 full days.

• 2.2 How much are you paying for the first 24 hours at P7? According to the P7 table, the cost for 8-24 hours is R270.00. You are paying $\boxed{\text{R}270.00}$ for the first 24 hours at P7.

• 2.3 How many 12 hours are there in 2 full days? First, calculate total hours: $2 \text{ days} \times 24 \text{ hours/day} = 48 \text{ hours}$. Then, divide by 12 hours: $\frac{48 \text{ hours}}{12 \text{ hours/block}} = 4 \text{ blocks}$. There are $\boxed{4 \text{ blocks of 12 hours}}$ in 2 full days.

• 2.4 What price will you pay for every 12 hours after the first 24 hours (at P7)? From the P7 notes, it states: "Thereafter R135.00 per 12 hours or part thereof." You will pay $\boxed{\text{R}135.00}$ for every 12 hours after the first 24 hours.

• 2.5 Calculate the cost of parking for 3 full days at P6 and P7. 3 full days = 72 hours.

  • Cost for P6 (72 hours): First 24 hours: R85.00 Remaining hours: $72 - 24 = 48$ hours. Number of 12-hour blocks thereafter = $\frac{48}{12} = 4$. $$$$