On six working days a garage mended 6, 5, 2, 3 and 2 punctures. Calculate the mean number of punctures per day mended by the garage. A. 2 B.3 C.4 D.5

The given numbers are 6, 5, 2, 3, 2. Assuming the sixth number is 2, the complete list is 6, 5, 2, 3, 2, 2.

There are 6 working days.

The mean is the sum of the numbers divided by the count of the numbers.

Looking at the options (A. 2, B. 3, C. 4, D. 5), none of them match 3.33 exactly. This suggests that my assumption for the sixth number might be incorrect, or there's a typo in the question or options.

Let's re-evaluate the problem statement. The question states "6, 5, 2, 3 and 2 punctures". This is only 5 numbers. If it's "six working days", there should be six numbers. It's possible the last number is cut off. Let's assume the last number is 2, making the list 6, 5, 2, 3, 2, 2. The mean is 3.33.

If the question meant there are only 5 days, and the list is 6, 5, 2, 3, 2:
Sum = $6+5+2+3+2 = 18$
Mean = $\frac{18}{5} = 3.6$

If the question meant there are 6 days, and the list is 6, 5, 2, 3, 2, and the last number is missing. Let's try to work backward from the options.
If the mean is 3 (Option B), then the sum of 6 numbers would be $3 \times 6 = 18$.
The sum of the visible numbers is $6+5+2+3+2 = 18$.
If the sum of the first five numbers is 18, and the total sum for six numbers is 18, then the sixth number must be $18 - 18 = 0$. This is unlikely for punctures.

Let's consider the possibility that the list of numbers is actually 6, 5, 2, 3, 2, and the last number is 2, as I initially assumed.
Sum = $6+5+2+3+2+2 = 20$.
Mean = $\frac{20}{6} = 3.33$.

Let's consider if the last number was 3.
Sum = $6+5+2+3+2+3 = 21$.
Mean = $\frac{21}{6} = 3.5$.

Given the options, it's highly probable that the question intends for the mean to be an integer. Let's re-read the question carefully: "On six working days a garage mended 6, 5, 2, 3 and 2 punctures." This explicitly lists only 5 numbers. If it's "six working days", there must be a sixth number.

Let's assume there are 6 numbers and the last number is missing from the image.
If the mean is 3 (Option B), then the total sum for 6 days must be $3 \times 6 = 18$.
The sum of the 5 visible numbers is $6+5+2+3+2 = 18$.
This implies the 6th number is $18 - 18 = 0$. This is a possible scenario if no punctures were mended on the 6th day.

If the mean is 4 (Option C), then the total sum for 6 days must be $4 \times 6 = 24$.
The sum of the 5 visible numbers is 18.
This implies the 6th number is $24 - 18 = 6$. This is a plausible number.

Let's assume the question meant the list of numbers is 6, 5, 2, 3, 2, and the sixth number is 6.

The numbers are 6, 5, 2, 3, 2, 6.

There are 6 working days.

This matches option C. This is the most reasonable interpretation given the options and the partial information.

The final answer is $\text{C. 4}$.