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A can complete a piece of work in 40 days. A and B together can complete the same work in 8 days. In how many days can B alone complete the work?

Mathematics

ScanSolve AI Answer

Answer

10 days\text{} 10 \text{ days} \text{}

Step-by-step solution

5 steps

here's the solution to this work-rate problem:

  1. Determine the individual work rate of A.

    A can complete the work in 40 days. So, A's one-day work rate is 140\frac{1}{40} of the total work.

  2. Determine the combined work rate of A and B.

    A and B together can complete the work in 8 days. So, their combined one-day work rate is 18\frac{1}{8} of the total work.

  3. Set up the equation to find B's work rate.

    The combined work rate of A and B is the sum of their individual work rates. Let B's one-day work rate be 1TB\frac{1}{T_B}, where TBT_B is the time B takes to complete the work alone.

    140+1TB=18\frac{1}{40} + \frac{1}{T_B} = \frac{1}{8}
  4. Solve for B's one-day work rate.

    Subtract A's work rate from the combined work rate:

    1TB=18−140\frac{1}{T_B} = \frac{1}{8} - \frac{1}{40}

    Find a common denominator, which is 40:

    1TB=540−140\frac{1}{T_B} = \frac{5}{40} - \frac{1}{40} 1TB=5−140\frac{1}{T_B} = \frac{5 - 1}{40} 1TB=440\frac{1}{T_B} = \frac{4}{40} 1TB=110\frac{1}{T_B} = \frac{1}{10}
  5. Determine the time B takes to complete the work alone.

    Since B's one-day work rate is 110\frac{1}{10}, B will take 10 days to complete the work alone.

    TB=10 daysT_B = 10 \text{ days}

    The final answer is 10 days\text{} 10 \text{ days} \text{}

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