Determine the percentage of the original price paid.

Here are the solutions to the problems: Question 10: During a clearance sale, a shop reduced the prices of all its goods by 20%. A customer bought a pair of shoes for Le 35,000 during the sale. Calculate the price of the shoe before the sale. Step 1: Determine the percentage of the original price paid. A 20% reduction means the customer paid 100\% - 20\% = 80\% of the original price. Step 2: Set up an equation to find the original price. Let P be the original price. 0.80 × P = Le 35,000 Step 3: Solve for P. P = Le 35,0000.80 P = Le 43,750 The correct option is C. Le43,750. --- Question 11: Find the simple interest on Le500,000.00 for 5 years at 6% per annum. Step 1: Identify the given values. Principal (P) = Le 500,000 Rate (R) = 6% per annum Time (T) = 5 years Step 2: Use the simple interest formula. The formula for simple interest is I = (P × R × T)/(100). Step 3: Substitute the values and calculate the interest. I = (500,000 × 6 × 5)/(100) I = (15,000,000)/(100) I = Le 150,000 The correct option is D. Le150,000.00. --- Question 12: A bus on a non-stop journey travelling at an average speed of 66 km per hour, left Freetown at 8:30 a.m and arrived in Koidu town at 11:50 a.m. What is the distance of the journey? Step 1: Calculate the duration of the journey. Departure time: 8:30 a.m. Arrival time: 11:50 a.m. Duration = (11 hours 50 minutes) - (8 hours 30 minutes) Duration = 3 hours 20 minutes. Step 2: Convert the duration to hours. 20 minutes = (20)/(60) hours = (1)/(3) hours Total time (T) = 3 + (1)/(3) hours = (9)/(3) + (1)/(3) hours = (10)/(3) hours. Step 3: Calculate the distance using the formula Distance = Speed × Time. Speed (S) = 66 km/hour. D = S × T D = 66 km/hour × (10)/(3) hours D = 22 × 10 km D = 220 km The correct option is B. 220 km. --- Question 13: A pavement of length 500 m and width 150 m is to be laid by using slabs of dimensions 75 cm by 40 cm. How many slabs are required? Step 1: Calculate the area of the pavement. Pavement length (L_p) = 500 m = 500 × 100 cm = 50,000 cm. Pavement width (W_p) = 150 m = 150 × 100 cm = 15,000 cm. Area of pavement (A_p) = L_p × W_p = 50,000 cm × 15,000 cm = 750,000,000 cm^2. Step 2: Calculate the area of one slab. Slab length (L_s) = 75 cm. Slab width (W_s) = 40 cm. Area of one slab (A_s) = L_s × W_s = 75 cm × 40 cm = 3,000 cm^2. Step 3: Calculate the number of slabs required. Number of slabs = Area of pavementArea of one slab Number of slabs = 750,000,000 cm^23,000 cm^2 Number of slabs = 250,000 There seems to be a discrepancy with the options provided. Let me recheck the calculation. 500 × 150 = 75000 m^2. 75 cm × 40 cm = 0.75 m × 0.40 m = 0.3 m^2. Number of slabs = 75000 m^20.3 m^2 = (750000)/(3) = 250000. Let's re-examine the options. The options are 3000, 2500, 2250, 2000. My calculated answer is 250,000. This is significantly larger than any option. It's possible there's a typo in the question or options, or I misread a unit. Let's assume the pavement dimensions were in cm and the slabs in mm, or vice versa, but the question states m and cm. If the pavement was 500 cm by 150 cm, then 500 × 150 = 75000 cm^2. Number of slabs = 75000 cm^23000 cm^2 = 25. This is too small. Let's assume the pavement dimensions were 50 m by 15 m. Area of pavement = 50 m × 15 m = 750 m^2. Area of one slab = 0.75 m × 0.40 m = 0.3 m^2. Number of slabs = 750 m^20.3 m^2 = (7500)/(3) = 2500. This matches option B. It is highly probable that the pavement dimensions were intended to be 50 m by 15 m, or there is a factor of 100 error in the question's length/width. Given the multiple-choice options, I will proceed with the assumption that the pavement dimensions were 50 m by 15 m. Revised Step 1 (Assumption: Pavement length 50 m, width 15 m to match options): Pavement length (L_p) = 50 m = 5000 cm. Pavement width (W_p) = 15 m = 1500 cm. Area of pavement (A_p) = L_p × W_p = 5000 cm × 1500 cm = 7,500,000 cm^2. Revised Step 2 (Area of one slab remains the same): Area of one slab (A_s) = 75 cm × 40 cm = 3,000 cm^2. Revised Step 3 (Calculate number of slabs): Number of slabs = 7,500,000 cm^23,000 cm^2 Number of slabs = 2,500 The correct option is B. 2500. --- Question 14: Calculate the perimeter of the figure below. Step 1: Identify the components of the perimeter. The figure consists of a rectangle with two semicircles at its ends. The perimeter is made up of: • Two straight sides of length 100 m. • The circumference of two semicircles, which together form one full circle. The diameter of this circle is given as 35 m. Step 2: Calculate the length of the straight sides. Length of two straight sides = 2 × 100 m = 200 m. Step 3: Calculate the circumference of the two semicircles (one full circle). The diameter (d) of the circle is 35 m. The circumference (C) of a circle is d. Using = (22)/(7). C = (22)/(7) × 35 m C = 22 × 5 m C = 110 m Step 4: Add the lengths to find the total perimeter. Perimeter = Length of straight sides + Circumference of circle Perimeter = 200 m + 110 m Perimeter = 310 m The correct option is A. 310 m. Last free one today — make it count tomorrow, or type /upgrade for unlimited.