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Calculate the perimeter of the composite figure shown in the image.

Mathematics

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Answer

186.55 mm\text{186.55 mm}

Step-by-step solution

2 steps

My apologies, Precious. I made an incorrect assumption in the previous response for 4.4. Let's correct it using the dimensions clearly visible in the image.

4.4

  1. Identify the components of the figure and their dimensions.

    The figure consists of a rectangular base and a semicircle on top.
    The vertical side of the rectangular part is 47 mm47 \text{ mm}.
    The horizontal side of the rectangular part (bottom) is 36 mm36 \text{ mm}.
    The diameter of the semicircle is the width of the rectangular part, which is 36 mm36 \text{ mm}.

  2. Calculate the perimeter.

    The perimeter consists of:

    • Two vertical sides of the rectangle: 47 mm+47 mm47 \text{ mm} + 47 \text{ mm}
    • The bottom horizontal side of the rectangle: 36 mm36 \text{ mm}
    • The arc length of the semicircle: 12×π×diameter\frac{1}{2} \times \pi \times \text{diameter}

    The formula for the arc length of a semicircle is L=12πdL = \frac{1}{2} \pi d, where dd is the diameter.
    Here, d=36 mmd = 36 \text{ mm}.

    P=47 mm+47 mm+36 mm+12π(36 mm)P = 47 \text{ mm} + 47 \text{ mm} + 36 \text{ mm} + \frac{1}{2} \pi (36 \text{ mm}) P=130 mm+18π mmP = 130 \text{ mm} + 18 \pi \text{ mm}

    Using π≈3.14159\pi \approx 3.14159:

    P≈130 mm+18×3.14159 mmP \approx 130 \text{ mm} + 18 \times 3.14159 \text{ mm} P≈130 mm+56.54862 mmP \approx 130 \text{ mm} + 56.54862 \text{ mm} P≈186.54862 mmP \approx 186.54862 \text{ mm}

    Rounding to two decimal places:

    P≈186.55 mmP \approx 186.55 \text{ mm}

    The perimeter of the figure is 186.55 mm\text{186.55 mm}.

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