Calculate the perimeter of the rectangle (top left figure).

The rectangle has a length of $24 \text{ cm}$ and a width of $16 \text{ cm}$.
The perimeter $P$ is given by $P = 2(L + W)$.

$$P = 2(24 \text{ cm} + 16 \text{ cm})$$ $$P = 2(40 \text{ cm})$$ $$P = 80 \text{ cm}$$

The outer sides are $4 \text{ cm}$ (bottom), $6 \text{ cm}$ (left vertical), $4 \text{ cm}$ (top left slant), $4 \text{ cm}$ (top right slant), and $6 \text{ cm}$ (right vertical).

$$P = 4 \text{ cm} + 6 \text{ cm} + 4 \text{ cm} + 4 \text{ cm} + 6 \text{ cm}$$ $$P = 24 \text{ cm}$$

The base is $9 \text{ cm}$. The tick marks indicate that the other two sides are equal. Assuming it is an equilateral triangle, all sides are $9 \text{ cm}$.

$$P = 9 \text{ cm} + 9 \text{ cm} + 9 \text{ cm}$$ $$P = 27 \text{ cm}$$

The figure shows a rectangle with a top side of $12 \text{ cm}$ and a right side of $4 \text{ cm}$. The internal lines are not part of the outer perimeter.
The perimeter $P$ is given by $P = 2(L + W)$.

$$P = 2(12 \text{ cm} + 4 \text{ cm})$$ $$P = 2(16 \text{ cm})$$ $$P = 32 \text{ cm}$$

The sides are $1.5 \text{ cm}$ (top), $10 \text{ cm}$ (left slant), $3 \text{ cm}$ (bottom), and $10 \text{ cm}$ (right slant).

$$P = 1.5 \text{ cm} + 10 \text{ cm} + 3 \text{ cm} + 10 \text{ cm}$$ $$P = 24.5 \text{ cm}$$