Write a Narrative essay of HL (150-200) & FAL (130-180) words on one of the topics listed below: 1. A life lesson you have learned 2. A frightening or dangerous experience you had. 3. An encounter with a stranger that left a lasting impact.

English
Write a Narrative essay of HL (150-200) & FAL (130-180) words on one of the topics listed below: 1. A life lesson you have learned 2. A frightening or dangerous experience you had. 3. An encounter with a stranger that left a lasting impact.

ScanSolve AI Answer

Answer

\epsilon = NBA\omega \sin(\omega t)

Step 1: Principle of operation based on electromagnetic induction.

The AC generator works on Faraday's law of electromagnetic induction. When the rectangular coil (armature) rotates in the uniform magnetic field between the north (N) and south (S) poles, the magnetic flux through the coil changes, inducing an emf.

Step 2: Magnetic flux through the coil.

Consider a coil with NN turns, each of area A=l×bA = l \times b (length ll, breadth bb), in magnetic field BB. Assume the field is perpendicular to the plane of the coil at t=0t=0.

Magnetic flux ϕ\phi through one turn: ϕ=BAcosθ\phi = B A \cos \theta

where θ\theta is the angle between the magnetic field B\mathbf{B} and the normal to the plane of the coil.

For NN turns: Φ=NBAcosθ\Phi = N B A \cos \theta

The coil rotates with constant angular velocity ω\omega, so θ=ωt\theta = \omega t.

Substitute: Φ=NBAcos(ωt)\Phi = N B A \cos (\omega t)

Units: Φ\Phi in Wb (webers), BB in T, AA in m², θ\theta dimensionless.

Step 3: Induced emf using Faraday's law.

ϵ=dΦdt\epsilon = -\frac{d\Phi}{dt}

Differentiate Φ\Phi: dΦdt=NBAddt[cos(ωt)]=NBA(ωsin(ωt))\frac{d\Phi}{dt} = N B A \frac{d}{dt} [\cos (\omega t)] = N B A (-\omega \sin (\omega t))

So, ϵ=[NBA(ωsin(ωt))]=NBAωsin(ωt)\epsilon = - [N B A (-\omega \sin (\omega t))] = N B A \omega \sin (\omega t)

Units: ϵ\epsilon in V, ω\omega in rad/s.

Step 4: Instantaneous and peak emf.

Instantaneous emf: ϵ(t)=ϵ0sin(ωt)\epsilon(t) = \epsilon_0 \sin (\omega t)

where peak emf ϵ0=NBAω\epsilon_0 = N B A \omega.

The emf alternates direction every half cycle (period T=2πωT = \frac{2\pi}{\omega}), producing alternating current (AC) in the external circuit via slip rings and brushes.

Step 5: Output to the bulb.

The alternating current flows through the slip rings, carbon brushes, and the bulb, causing it to light up due to heating effect of the current.

Final answer: Induced emf is ϵ=NBAωsin(ωt)\epsilon = NBA\omega \sin(\omega t) V

\epsilon = NBA\omega \sin(\omega t)

Was this helpful?

Need help with your own homework?

Get instant step-by-step solutions to any question. Free to start.

Ask Your Question

Still have questions?

Quick Answer

Principle of operation based on electromagnetic induction. The AC generator works on Faraday's law of electromagnetic induction.

Write a Narrative essay of HL (150-200) & FAL (130-180) words on one of the topics listed below: 1. A life lesson you have learned 2. A frightening or dangerous experience you had. 3. An encounter with a stranger that left a lasting impact.
English

This English question involves literary analysis, grammar, or writing skills. The detailed response below provides a well-structured answer with supporting evidence and clear explanations.

ScanSolve AI Answer
Step 1: Principle of operation based on electromagnetic induction. The AC generator works on Faraday's law of electromagnetic induction. When the rectangular coil (armature) rotates in the uniform magnetic field between the north (N) and south (S) poles, the magnetic flux through the coil changes, inducing an emf. Step 2: Magnetic flux through the coil. Consider a coil with N turns, each of area A = l × b (length l, breadth b), in magnetic field B. Assume the field is perpendicular to the plane of the coil at t=0. Magnetic flux through one turn: = B A where is the angle between the magnetic field B and the normal to the plane of the coil. For N turns: = N B A The coil rotates with constant angular velocity , so = t. Substitute: = N B A ( t) Units: in Wb (webers), B in T, A in m², dimensionless. Step 3: Induced emf using Faraday's law. = -(d)/(dt) Differentiate : (d)/(dt) = N B A (d)/(dt) [ ( t)] = N B A (- ( t)) So, = - [N B A (- ( t))] = N B A ( t) Units: in V, in rad/s. Step 4: Instantaneous and peak emf. Instantaneous emf: (t) = _0 ( t) where peak emf _0 = N B A . The emf alternates direction every half cycle (period T = (2)/()), producing alternating current (AC) in the external circuit via slip rings and brushes. Step 5: Output to the bulb. The alternating current flows through the slip rings, carbon brushes, and the bulb, causing it to light up due to heating effect of the current. Final answer: Induced emf is = NBA ( t) V = NBA ( t)