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Define Probability and state its Axioms.

Mathematics

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23\frac{2}{3}

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  1. Define Probability and state its Axioms.

    • a) Probability is a numerical measure of the likelihood that an event will occur. It is quantified as a number between 0 and 1, where 0 indicates impossibility and 1 indicates certainty.

      The Axioms of Probability (Kolmogorov's Axioms) are:

      1. Non-negativity: For any event AA, the probability of AA is non-negative. P(A)≥0P(A) \ge 0
      2. Normalization: The probability of the sample space SS (the set of all possible outcomes) is 1. P(S)=1P(S) = 1
      3. Countable Additivity: For any sequence of mutually exclusive events A1,A2,A3,…A_1, A_2, A_3, \dots (events that cannot occur at the same time), the probability of their union is the sum of their individual probabilities. P(A1∪A2∪A3∪… )=P(A1)+P(A2)+P(A3)+…P(A_1 \cup A_2 \cup A_3 \cup \dots) = P(A_1) + P(A_2) + P(A_3) + \dots
  2. Write short notes on the given terms.

    • b)
      • i) An Experiment is any process that yields an observation or an outcome. For example, tossing a coin or rolling a die.
      • ii) A Sample Space (SS) is the set of all possible outcomes of a random experiment. For example, when rolling a die, S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}.
      • iii) An Event Space (or simply an Event) is a subset of the sample space, consisting of one or more outcomes. For example, rolling an even number on a die is an event E={2,4,6}E = \{2, 4, 6\}.
      • iv) A Sample Point is an individual outcome in the sample space. For example, when rolling a die, '3' is a sample point.
      • v) Trials are individual repetitions of an experiment. For example, if you toss a coin 10 times, each toss is a trial.
  3. Calculate the probability of not getting a perfect square.

    • c) When a fair die is tossed once, the sample space is S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}. The total number of possible outcomes is 6. The perfect squares in this sample space are {1,4}\{1, 4\}. Let AA be the event that a perfect square shows up. The number of outcomes in event AA is 2. The probability of event AA is: P(A)=Number of perfect squaresTotal number of outcomes=26=13P(A) = \frac{\text{Number of perfect squares}}{\text{Total number of outcomes}} = \frac{2}{6} = \frac{1}{3} The probability that a perfect square did not show up is P(A′)P(A'), which is 1−P(A)1 - P(A). P(A′)=1−P(A)=1−13=23P(A') = 1 - P(A) = 1 - \frac{1}{3} = \frac{2}{3} The probability that a perfect square did not show up is 23\boxed{\frac{2}{3}}.
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