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Evaluate the probability P(0.5 2264 X 2264 1.5).

Mathematics

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Answer

1116\frac{11}{16}

Step-by-step solution

4 steps

Here's the evaluation of the probability:

To evaluate the probability P(0.5≤X≤1.5)P(0.5 \le X \le 1.5), we use the Cumulative Distribution Function (CDF) F(x)=3x24−x34F(x) = \frac{3x^2}{4} - \frac{x^3}{4}. The probability is given by P(0.5≤X≤1.5)=F(1.5)−F(0.5)P(0.5 \le X \le 1.5) = F(1.5) - F(0.5).

  1. Calculate F(1.5)F(1.5).

    Substitute x=1.5x = 1.5 (or 32\frac{3}{2}) into the CDF:

    F(1.5)=3(1.5)24−(1.5)34F(1.5) = \frac{3(1.5)^2}{4} - \frac{(1.5)^3}{4} F(1.5)=3(32)24−(32)34F(1.5) = \frac{3\left(\frac{3}{2}\right)^2}{4} - \frac{\left(\frac{3}{2}\right)^3}{4} F(1.5)=3(94)4−2784F(1.5) = \frac{3\left(\frac{9}{4}\right)}{4} - \frac{\frac{27}{8}}{4} F(1.5)=2744−2732F(1.5) = \frac{\frac{27}{4}}{4} - \frac{27}{32} F(1.5)=2716−2732F(1.5) = \frac{27}{16} - \frac{27}{32}

    To subtract, find a common denominator, which is 32:

    F(1.5)=27×216×2−2732=5432−2732=2732F(1.5) = \frac{27 \times 2}{16 \times 2} - \frac{27}{32} = \frac{54}{32} - \frac{27}{32} = \frac{27}{32}
  2. Calculate F(0.5)F(0.5).

    Substitute x=0.5x = 0.5 (or 12\frac{1}{2}) into the CDF:

    F(0.5)=3(0.5)24−(0.5)34F(0.5) = \frac{3(0.5)^2}{4} - \frac{(0.5)^3}{4} F(0.5)=3(12)24−(12)34F(0.5) = \frac{3\left(\frac{1}{2}\right)^2}{4} - \frac{\left(\frac{1}{2}\right)^3}{4} F(0.5)=3(14)4−184F(0.5) = \frac{3\left(\frac{1}{4}\right)}{4} - \frac{\frac{1}{8}}{4} F(0.5)=344−132F(0.5) = \frac{\frac{3}{4}}{4} - \frac{1}{32} F(0.5)=316−132F(0.5) = \frac{3}{16} - \frac{1}{32}

    To subtract, find a common denominator, which is 32:

    F(0.5)=3×216×2−132=632−132=532F(0.5) = \frac{3 \times 2}{16 \times 2} - \frac{1}{32} = \frac{6}{32} - \frac{1}{32} = \frac{5}{32}
  3. Calculate P(0.5≤X≤1.5)P(0.5 \le X \le 1.5).

    P(0.5≤X≤1.5)=F(1.5)−F(0.5)P(0.5 \le X \le 1.5) = F(1.5) - F(0.5) P(0.5≤X≤1.5)=2732−532P(0.5 \le X \le 1.5) = \frac{27}{32} - \frac{5}{32} P(0.5≤X≤1.5)=27−532=2232P(0.5 \le X \le 1.5) = \frac{27 - 5}{32} = \frac{22}{32}
  4. Simplify the fraction

    P(0.5≤X≤1.5)=1116P(0.5 \le X \le 1.5) = \frac{11}{16}

    The probability is 1116\frac{11}{16}.

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