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Calculate the conditional probability P(COM 201 | COM 101), given P(COM 101 and COM 201) = 0.0125 and P(COM 101) = 0.125.

Mathematics

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Answer

e

a) 0.1\text{a) } 0.1

Step-by-step solution

3 steps

This problem requires calculating a conditional probability.

Let C101C_{101} be the event that a student takes COM 101.
Let C201C_{201} be the event that a student takes COM 201.

We are given:

  • The probability that a student takes COM 101 and COM 201 in the same semester: P(C101 and C201)=0.0125P(C_{101} \text{ and } C_{201}) = 0.0125.
  • The probability that a student takes COM 101: P(C101)=0.125P(C_{101}) = 0.125.

We need to find the probability that a student is taking COM 201, given that he or she is taking COM 101. This is written as P(C201∣C101)P(C_{201} | C_{101}).

The formula for conditional probability is:

P(A∣B)=P(A and B)P(B)P(A|B) = \frac{P(A \text{ and } B)}{P(B)}
  1. Identify the given probabilities.

    P(C201 and C101)=0.0125P(C_{201} \text{ and } C_{101}) = 0.0125 P(C101)=0.125P(C_{101}) = 0.125
  2. Apply the conditional probability formula.

    P(C201∣C101)=P(C201 and C101)P(C101)P(C_{201} | C_{101}) = \frac{P(C_{201} \text{ and } C_{101})}{P(C_{101})} P(C201∣C101)=0.01250.125P(C_{201} | C_{101}) = \frac{0.0125}{0.125}
  3. Calculate the result.

    P(C201∣C101)=0.1P(C_{201} | C_{101}) = 0.1

    Comparing this result with the given options:

    a) 0.1

    b) 0.1125

    c) 0.0016

    d) 0.1375

    e) 0.4800

    The calculated probability matches option (a).

    The final answer is a) 0.1\boxed{\text{a) } 0.1}.

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