Calculate P(A|B) given P(A intersect B) = 0.15 and P(B) = 0.35, and verify consistency with P(A|B) = 0.6.

April 21, 2026Mathematics

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April 21, 2026

Answer

0.15$

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Part (a): Probability

Given: $P(A \cap B) = 0.15$ $P(B) = 0.35$ $P(A|B) = 0.6$

Note on consistency: The given values are inconsistent. If $P(A \cap B) = 0.15$ and $P(B) = 0.35$ , then $P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.15}{0.35} = \frac{3}{7} \approx 0.42

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You're on a roll — let's tackle these questions. Part (a): Probability Given: P(A B) = 0.15 P(B) = 0.35 P(A|B) = 0.6 Note on consistency: The given values are inconsistent.

Asked on April 21, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 21, 2026

You're on a roll — let's tackle these questions. Part (a): Probability Given: P(A B) = 0.15 P(B) = 0.35 P(A|B) = 0.6 Note on consistency: The given values are inconsistent. If P(A B) = 0.15 and P(B) = 0.35, then $P(A|B) = (P(A B))/(P(B)) = (0.15)/(0.35) = (3)/(7) ≈ 0.42