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Calculate P(A|B) given P(A intersect B) = 0.15 and P(B) = 0.35, and verify consistency with P(A|B) = 0.6.

Mathematics

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Part (a): Probability

Given:
P(A∩B)=0.15P(A \cap B) = 0.15
P(B)=0.35P(B) = 0.35
P(A∣B)=0.6P(A|B) = 0.6

Note on consistency: The given values are inconsistent. If P(A∩B)=0.15P(A \cap B) = 0.15 and P(B)=0.35P(B) = 0.35, then $P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.15}{0.35} = \frac{3}{7} \approx 0.42

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