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Problem 12: Atim had 200 oranges. He sold them in groups of 4 oranges each for sh 1,500 per group. How much money did Atim get from selling all the oranges? Problem 13: Find the median of the followin

Mathematics

ScanSolve AI Answer

Answer

10

Step-by-step solution

4 steps

:

  1. Determine how many groups of 4 oranges Atim sold.

    Number of groups=Total orangesOranges per group=2004=50\text{Number of groups} = \frac{\text{Total oranges}}{\text{Oranges per group}} = \frac{200}{4} = 50

    Atim sold 50 groups of 4 oranges.

  2. Calculate the total amount of money Atim received.

    Since each group of 4 oranges was sold for sh 1,500, multiply the number of groups by the price per group.

    Total money=Number of groups×Price per group=50×sh 1,500=sh 75,000\text{Total money} = \text{Number of groups} \times \text{Price per group} = 50 \times \text{sh } 1,500 = \text{sh } 75,000

    The amount of money Atim got from selling all the oranges is sh 75,000.

    :

  3. Arrange the given numbers in ascending order.

    The numbers are 6, 13, 7, 11, 15, 9.
    Arranged in ascending order: 6, 7, 9, 11, 13, 15.

  4. Find the median.

    Since there is an even number of values (6 numbers), the median is the average of the two middle numbers. The middle numbers are the 3rd and 4th values, which are 9 and 11.

    Median=9+112=202=10\text{Median} = \frac{9 + 11}{2} = \frac{20}{2} = 10

    The median of the given numbers is 10.

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