Solve problems 5(b) and 6(a-f) involving multiplication of fractions and finding a fraction of a number.

$$
= \frac{49}{7} \times \frac{52}{16} \times \frac{25}{39}
$$
$$
= 7 \times \frac{13 \times 4}{4 \times 4} \times \frac{25}{3 \times 13}
$$
$$
= 7 \times \frac{13}{4} \times \frac{25}{3 \times 13}
$$
$$
= \frac{7 \times 25}{4 \times 3} = \frac{175}{12}
$$
$$
\boxed{\frac{175}{12}}
$$

6. Find.

• (a) $\frac{1}{3}$ of 24}

  $$\frac{1}{3} \times 24 = \frac{24}{3} = \boxed{8}$$

• (b) $\frac{3}{4}$ of 32}

  $$\frac{3}{4} \times 32 = 3 \times \frac{32}{4} = 3 \times 8 = \boxed{24}$$

• (c) $\frac{5}{9}$ of 45}

  $$\frac{5}{9} \times 45 = 5 \times \frac{45}{9} = 5 \times 5 = \boxed{25}$$

• (d) $\frac{7}{5}$ of 100}

  $$\frac{7}{5} \times 100 = 7 \times \frac{100}{5} = 7 \times 20 = \boxed{140}$$

• (e) $\frac{5}{11}$ of 220}

  $$\frac{5}{11} \times 220 = 5 \times \frac{220}{11} = 5 \times 20 = \boxed{100}$$

• (f) $\frac{3}{2}$ of 102}

  $$\frac{3}{2} \times 102 = 3 \times \frac{102}{2} = 3 \times 51 = \boxed{153}$$

7. Find.

• (i) $\frac{4}{9}$ of 54 metres

  $$\frac{4}{9} \times 54 \text{ m} = 4 \times 6 \text{ m} = \boxed{24 \text{ m}}$$

• (ii) $\frac{6}{7}$ of 35 litres

  $$\frac{6}{7} \times 35 \text{ litres} = 6 \times 5 \text{ litres} = \boxed{30 \text{ litres}}$$

• (iii) $\frac{1}{4}$ of an hour

  $$\frac{1}{4} \times 60 \text{ minutes} = \boxed{15 \text{ minutes}}$$

• (iv) $\frac{5}{6}$ of a year

  $$\frac{5}{6} \times 12 \text{ months} = 5 \times 2 \text{ months} = \boxed{10 \text{ months}}$$

• **(v) $\frac{7}{20}$ of a kilogram