Find equivalent fractions for the given fractions and then add the fractions. Problems a-f for equivalent fractions and then add 1/2 + 1/2.

Here are the solutions to the problems. Step 1: Complete equivalent fractions To find equivalent fractions, multiply both the numerator and the denominator by the same non-zero number. *a) For (1)/(3): (1)/(3) = (1 × 2)/(3 × 2) = (2)/(6) (1)/(3) = (1 × 3)/(3 × 3) = (3)/(9) *b) For (1)/(4): (1)/(4) = (1 × 2)/(4 × 2) = (2)/(8) (1)/(4) = (1 × 3)/(4 × 3) = (3)/(12) *c) For (1)/(5): (1)/(5) = (1 × 2)/(5 × 2) = (2)/(10) (1)/(5) = (1 × 3)/(5 × 3) = (3)/(15) *d) For (1)/(6): (1)/(6) = (1 × 2)/(6 × 2) = (2)/(12) (1)/(6) = (1 × 3)/(6 × 3) = (3)/(18) *e) For (1)/(7): (1)/(7) = (1 × 2)/(7 × 2) = (2)/(14) (1)/(7) = (1 × 3)/(7 × 3) = (3)/(21) *f) For (1)/(8): (1)/(8) = (1 × 2)/(8 × 2) = (2)/(16) (1)/(8) = (1 × 3)/(8 × 3) = (3)/(24) Step 2: Add the fractions To add fractions with the same denominator, add the numerators and keep the denominator the same. Simplify the result if possible. *a) (1)/(2) + (1)/(2) = (1+1)/(2) = (2)/(2) = 1 *b) (1)/(3) + (1)/(3) = (1+1)/(3) = (2)/(3) *c) (1)/(4) + (1)/(4) = (1+1)/(4) = (2)/(4) = (1)/(2) *d) (1)/(5) + (1)/(5) = (1+1)/(5) = (2)/(5) *e) (1)/(6) + (1)/(6) = (1+1)/(6) = (2)/(6) = (1)/(3) *f) (1)/(7) + (1)/(7) = (1+1)/(7) = (2)/(7) *g) (1)/(8) + (1)/(8) = (1+1)/(8) = (2)/(8) = (1)/(4) *h) (1)/(9) + (1)/(9) = (1+1)/(9) = (2)/(9) *i) (1)/(10) + (1)/(10) = (1+1)/(10) = (2)/(10) = (1)/(5) *j) (2)/(5) + (1)/(5) = (2+1)/(5) = (3)/(5) *k) (3)/(6) + (1)/(6) = (3+1)/(6) = (4)/(6) = (2)/(3) *l) (4)/(7) + (2)/(7) = (4+2)/(7) = (6)/(7) *m) (5)/(8) + (1)/(8) = (5+1)/(8) = (6)/(8) = (3)/(4) *n) (6)/(9) + (2)/(9) = (6+2)/(9) = (8)/(9) *o) (7)/(10) + (1)/(10) = (7+1)/(10) = (8)/(10) = (4)/(5) *p) (8)/(11) + (2)/(11) = (8+2)/(11) = (10)/(11) *q) (9)/(12) + (1)/(12) = (9+1)/(12) = (10)/(12) = (5)/(6) *r) $(10)/(13) + (2)/(13) = (10+2)/(13) = 121