Please provide solutions for the following loan problems: 1. Calculate the total repayment amount for borrowing R 3000 over 24 months. 2. Determine the ratio of monthly installments for R2000 over 12

Here are the solutions to the loan problems:

Calculate the total repayment amount for borrowing R 3000 when repaying it over 24 months.

Step 1: Identify the monthly instalment from the table.
For a loan amount of R 3000 over 24 months, the monthly instalment is R 230.

Step 2: Calculate the total repayment amount.
Total repayment = Monthly instalment $\times$ Number of months

$$\text{Total repayment} = \text{R}230 \times 24$$ $$\text{Total repayment} = \text{R}5520$$

The total repayment amount is R 5520.

$$\boxed{\text{R}5520}$$

Determine the ratio in its simplest form, of A to B, the monthly instalment for borrowing R2 000.

Step 1: Identify the values for A and B from the table.
For a loan amount of R 2000:
A (12 months instalment) = R 285
B (24 months instalment) = R 190

Step 2: Write the ratio A to B.

$$\text{Ratio A : B} = 285 : 190$$

Step 3: Simplify the ratio by dividing both numbers by their greatest common divisor.
Both numbers are divisible by 5:

$$285 \div 5 = 57$$ $$190 \div 5 = 38$$

The ratio becomes $57 : 38$.
Both numbers are divisible by 19:

$$57 \div 19 = 3$$ $$38 \div 19 = 2$$

The ratio in its simplest form is 3 : 2.

$$\boxed{3 : 2}$$

A customer borrowed R4 000 and plans to pay it in equal monthly instalments for 3 years. The customer was charged 30% pa. simple interest.