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Please provide solutions for the following questions: 2.3, 7.3, 7.3.1, and 8.2.

Mathematics

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2.3) A factor produces 1280 boxes in 8 days. How many boxes are produced in 28 days?

  1. Calculate the production rate per day.

    Rate=1280 boxes8 days=160 boxes/day\text{Rate} = \frac{1280 \text{ boxes}}{8 \text{ days}} = 160 \text{ boxes/day}
  2. Calculate the total boxes produced in 28 days.

    Total boxes=160 boxes/day×28 days=4480 boxes\text{Total boxes} = 160 \text{ boxes/day} \times 28 \text{ days} = 4480 \text{ boxes}

    The factory produces 4480 boxes\boxed{\text{4480 boxes}} in 28 days.

    7.3) Expand 3(x+2)23(x+2)^2

  3. Expand the squared term (x+2)2(x+2)^2.

    (x+2)2=x2+2(x)(2)+22=x2+4x+4(x+2)^2 = x^2 + 2(x)(2) + 2^2 = x^2 + 4x + 4
  4. Multiply the result by 3.

    3(x2+4x+4)=3x2+12x+123(x^2 + 4x + 4) = 3x^2 + 12x + 12

    The expanded expression is 3x2+12x+12\boxed{3x^2 + 12x + 12}.

    7.3.1) Simplify x2−9x2−3x\frac{x^2-9}{x^2-3x}

  5. Factor the numerator using the difference of squares formula (a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b)).

    x2−9=x2−32=(x−3)(x+3)x^2 - 9 = x^2 - 3^2 = (x-3)(x+3)
  6. Factor the denominator by taking out the common factor xx.

    x2−3x=x(x−3)x^2 - 3x = x(x-3)
  7. Substitute the factored expressions back into the fraction and simplify by canceling common factors.

    x2−9x2−3x=(x−3)(x+3)x(x−3)=x+3x\frac{x^2-9}{x^2-3x} = \frac{(x-3)(x+3)}{x(x-3)} = \frac{x+3}{x}

    The simplified expression is x+3x\boxed{\frac{x+3}{x}}.

    8.2) A number is multiply by 7 and then decrease by 12. The result is 23. Write and solve an equation to find the number.

  8. Let the unknown number be xx.

  9. Write the equation based on the problem description.

    7x−12=237x - 12 = 23
  10. Solve the equation for xx.

    7x−12=237x - 12 = 23 7x=23+127x = 23 + 12 7x=357x = 35 x=357x = \frac{35}{7} x=5x = 5

    The number is 5\boxed{5}.

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