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What are the solutions to questions 4, 5, and 6?

Mathematics

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4. Express 72 as a product of its prime factors using a factor tree. (3 marks)

  1. Start with 72 and find two factors.

    72=2×3672 = 2 \times 36
  2. Continue factoring until all branches end in prime numbers.

    36=2×1836 = 2 \times 18 18=2×918 = 2 \times 9 9=3×39 = 3 \times 3
  3. Collect all the prime factors.

    72=2×2×2×3×372 = 2 \times 2 \times 2 \times 3 \times 3 72=23×3272 = 2^3 \times 3^2

    The prime factors of 72 are 2×2×2×3×32 \times 2 \times 2 \times 3 \times 3.
    The product of its prime factors is 23×32\boxed{2^3 \times 3^2}.

    5. The cube below was used to hold milk. What is the volume of the cube? (3 marks)

  4. Identify the side length of the cube from the image.

    The side length of the cube is 20 cm20 \text{ cm}.

  5. Use the formula for the volume of a cube.

    The volume VV of a cube with side length ss is V=s3V = s^3.

  6. Substitute the side length into the formula and calculate.

    V=(20 cm)3V = (20 \text{ cm})^3 V=20 cm×20 cm×20 cmV = 20 \text{ cm} \times 20 \text{ cm} \times 20 \text{ cm} V=8000 cm3V = 8000 \text{ cm}^3

    The volume of the cube is 8000 cm3\boxed{8000 \text{ cm}^3}.

    6. Salome had 6 oranges, Moraa had 18 of them while Jeremy had 12 oranges. What is the L.C.M of the numbers? (3 marks)

  7. List the numbers given.

    The numbers are 6, 18, and 12.

  8. Find the prime factorization of each number.

    6=2×36 = 2 \times 3 18=2×3×3=2×3218 = 2 \times 3 \times 3 = 2 \times 3^2 12=2×2×3=22×312 = 2 \times 2 \times 3 = 2^2 \times 3
  9. To find the L.C.M, take the highest power of each prime factor present in any of the numbers.

    The prime factors are 2 and 3.
    The highest power of 2 is 222^2 (from 12).
    The highest power of 3 is 323^2 (from 18).

  10. Multiply these highest powers together.

    L.C.M=22×32\text{L.C.M} = 2^2 \times 3^2 L.C.M=4×9\text{L.C.M} = 4 \times 9 L.C.M=36\text{L.C.M} = 36

    The L.C.M of 6, 18, and 12 is 36\boxed{36}.

    10. Simplify the expression 5x+20+8x+105x + 20 + 8x + 10.

  11. Group like terms together.

    5x+8x+20+105x + 8x + 20 + 10
  12. Combine the xx terms.

    5x+8x=13x5x + 8x = 13x
  13. Combine the constant terms.

    20+10=3020 + 10 = 30
  14. Write the simplified expression.

    13x+3013x + 30

    The simplified expression is 13x+30\boxed{13x + 30}.

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