We read your photo as:

Quadrilateral ABCD is a kite. Calculate: i) Length of BD, ii) Length of AE, iii) Size of DAB

Mathematics

ScanSolve AI Answer

Answers

3 parts
a(i)

6 cm\text{6 cm}

a(ii)

3.58 cm\text{3.58 cm}

a(iii)

80°\text{80°}

Step-by-step solution

3 steps

The problem asks us to calculate the length of BD, the length of AE, and the size of angle DAB for a kite ABCD.

From the diagram:

  • The quadrilateral ABCD is a kite.
  • The diagonals AC and BD intersect at point E.
  • The diagonals are perpendicular, indicated by the square symbol at E.
  • The length DE is given as 3 cm.
  • An angle is given as 40 degrees. This angle is drawn at vertex B, between segments BE and BC, so it represents ∠CBE=40∘\angle CBE = 40^\circ.

However, if ∠CBE=40∘\angle CBE = 40^\circ, we cannot determine the length of AE or the size of ∠DAB\angle DAB with the given information. A common setup for such problems is that the angle provided is one of the angles in the upper triangle, △AED\triangle AED. Given that all parts of the question are expected to be solvable, we will assume that the 40-degree angle is actually ∠DAE\angle DAE (or ∠BAE\angle BAE), despite its placement in the diagram. This assumption allows us to solve for all requested values.

Assumption: The 40-degree angle is ∠DAE=40∘\angle DAE = 40^\circ.

Part a(i)· 1 step

Length of BD

Calculate

  1. Use the properties of a kite.

    In a kite, the main diagonal (AC) is the perpendicular bisector of the other diagonal (BD). This means that point E is the midpoint of BD, so BE = ED.
    Given DE = 3 cm.

    BE=DE=3 cmBE = DE = 3 \text{ cm}

    The length of the diagonal BD is the sum of BE and ED.

    BD=BE+ED=3 cm+3 cm=6 cmBD = BE + ED = 3 \text{ cm} + 3 \text{ cm} = 6 \text{ cm}

    The length of BD is 6 cm\boxed{\text{6 cm}}.

Part a(ii)

3.58 cm\text{3.58 cm}

Length of AE

  1. Use trigonometry in △AED\triangle AED.

    △AED\triangle AED is a right-angled triangle at E (since diagonals are perpendicular).
    We have DE = 3 cm and, by our assumption, ∠DAE=40∘\angle DAE = 40^\circ.
    We can use the tangent function, which relates the opposite side (DE) to the adjacent side (AE) with respect to ∠DAE\angle DAE.

    tan⁡(∠DAE)=oppositeadjacent=DEAE\tan(\angle DAE) = \frac{\text{opposite}}{\text{adjacent}} = \frac{DE}{AE} tan⁡(40∘)=3AE\tan(40^\circ) = \frac{3}{AE}

    Now, solve for AE:

    AE=3tan⁡(40∘)AE = \frac{3}{\tan(40^\circ)}

    Using a calculator, tan⁡(40∘)≈0.8391\tan(40^\circ) \approx 0.8391.

    AE=30.8391≈3.5752 cmAE = \frac{3}{0.8391} \approx 3.5752 \text{ cm}

    Rounding to two decimal places:
    The length of AE is approximately 3.58 cm\boxed{\text{3.58 cm}}.

Part a(iii)

80°\text{80°}

Size of DAB

  1. Use the properties of a kite for angles.

    In a kite, the main diagonal (AC) bisects the angles at the vertices it connects. Therefore, AC bisects ∠DAB\angle DAB.
    This means ∠DAB=2×∠DAE\angle DAB = 2 \times \angle DAE.
    Since we assumed ∠DAE=40∘\angle DAE = 40^\circ:

    ∠DAB=2×40∘=80∘\angle DAB = 2 \times 40^\circ = 80^\circ

    The size of ∠DAB\angle DAB is 80°\boxed{\text{80°}}.

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp