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Question 21: a) Find the sum of 2 and 6. b) Calculate the product of 6 and 3. c) Divide 2 by 5. Question 22: a) Represent info on Venn diagram. b) How many guests took both drinks?

Mathematics

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Question 21:

a) Find the sum of the values of 2 and 6.

  1. Add the numbers.

    2+6=82 + 6 = 8

    The sum is 8\boxed{8}.

    b) Calculate the product of the values of 6 and 3.

  2. Multiply the numbers.

    6×3=186 \times 3 = 18

    The product is 18\boxed{18}.

    c) Divide the value of 2 by the value of 5.

  3. Perform the division.

    25=0.4\frac{2}{5} = 0.4

    The result is 0.4\boxed{0.4}.

    Question 22:

    a) Represent the information on the Venn diagram.
    The provided image already contains a Venn diagram with the following labels, which correctly represent the given information:

    • Universal set N(Σ)=50N(\Sigma) = 50.
    • Set for Soda n(S)=30n(S) = 30.
    • Set for Beer n(B)=25n(B) = 25.
    • Region for only Soda: 30−Y30 - Y.
    • Region for both (intersection): YY.
    • Region for only Beer: 25−Y25 - Y.
    • Region for neither (outside circles): 3.

    b) How many guests took both drinks?

  4. Use the principle of inclusion-exclusion.

    The total number of guests is the sum of those who took only soda, only beer, both drinks, and none of the drinks.

    N(Σ)=(only soda)+(only beer)+(both)+(none)N(\Sigma) = (\text{only soda}) + (\text{only beer}) + (\text{both}) + (\text{none}) 50=(30−Y)+(25−Y)+Y+350 = (30 - Y) + (25 - Y) + Y + 3
  5. Simplify the equation.

    50=30−Y+25−Y+Y+350 = 30 - Y + 25 - Y + Y + 3 50=(30+25+3)+(−Y−Y+Y)50 = (30 + 25 + 3) + (-Y - Y + Y) 50=58−Y50 = 58 - Y
  6. Solve for YY.

    Y=58−50Y = 58 - 50 Y=8Y = 8

    The number of guests who took both drinks is 8\boxed{8}.

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