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R1 the lef of his. Muska bought the following items: £89 + £120.80 = £209.80.

Mathematics

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2 parts
4
6
6

K152.30\text{K}152.30

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Part 4· 4 steps

Find the HCF of 12 and 18.

  1. Find the prime factorization of 12.

    12=2×2×3=22×3112 = 2 \times 2 \times 3 = 2^{2} \times 3^{1}

  2. Find the prime factorization of 18.

    18=2×3×3=21×3218 = 2 \times 3 \times 3 = 2^{1} \times 3^{2}

  3. Identify the common prime factors and take the lowest power for each.

    The common prime factors are 2 and 3.
    The lowest power of 2 is 212^{1}.
    The lowest power of 3 is 313^{1}.

  4. Multiply these lowest powers together to find the HCF.

    HCF=21×31=2×3=6\text{HCF} = 2^{1} \times 3^{1} = 2 \times 3 = 6

    The HCF of 12 and 18 is 6\boxed{6}.

Part 6

K152.30\text{K}152.30

Musa bought the following items: Bread K23.50, Sugar K8.00 and a pair of Shoes K120.80. (Find the total cost)

  1. List the cost of each item.

    Bread: K23.50
    Sugar: K8.00
    Shoes: K120.80

  2. Add the costs of all items to find the total.

    Total Cost=K23.50+K8.00+K120.80\text{Total Cost} = \text{K}23.50 + \text{K}8.00 + \text{K}120.80

  3. Perform the addition.

    23.508.00+120.80152.30\begin{array}{r} 23.50 \\ 8.00 \\ + 120.80 \\ \hline 152.30 \\ \end{array}

    The total cost of the items Musa bought is K152.30\boxed{\text{K}152.30}.

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