Translate the following word problems into algebraic equations: You buy three cans of coke and pay with R10, receiving R2.20 change. Four adults cost R148. Eight metres of material cost R116. R550 is

The cost of one can of coke is $R x$.
You buy three cans, so the total cost of coke is $3x$.
You pay with $R10$ and receive $R 2.20$ change.

The amount paid minus the total cost of the items equals the change received.

The equation is $\boxed{10 - 3x = 2.20}$.

3.

The cost for four adults is $R148$.
Let $y$ be the cost for one adult.

The cost for four adults is 4 times the cost for one adult.

The equation is $\boxed{4y = 148}$.

4.

The cost of one metre of material is $R x$.
You want to find the cost of 8 metres, which is $8x$.
It is given that 8 metres cost $R116$.

The total cost of 8 metres is equal to $R116$.

The equation is $\boxed{8x = 116}$.

5.

Let $k$ be the exchange rate, representing how many Malawian Kwacha you get for one Rand.
If you have $R550$, you get $11 550$ Kwacha.

The total Kwacha received is the amount of Rand multiplied by the exchange rate.

The equation is $\boxed{550k = 11550}$.