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Find the rate of interest in P.C.P.A. by which Rs. 900 will amounts to Rs. 1089 in two years? A washing machine was purchased for Rs. 2100. After 1 year the price were reduced by 5%. What will be pric

Mathematics

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Here are the solutions to the problems.

Q1. Find the rate of interest in P.C.P.A. by which Rs. 900 will amounts to Rs. 1089 in two years?

  1. Identify the given values.

    Principal (PP) = Rs. 900
    Amount (AA) = Rs. 1089
    Time (nn) = 2 years
    Rate of interest (RR) = ?

  2. Use the compound interest formula for amount

    A=P(1+R100)nA = P\left(1 + \frac{R}{100}\right)^n.
    Substitute the given values into the formula:

    1089=900(1+R100)21089 = 900\left(1 + \frac{R}{100}\right)^2
  3. Isolate the term with RR.

    1089900=(1+R100)2\frac{1089}{900} = \left(1 + \frac{R}{100}\right)^2
  4. Simplify the fraction and take the square root of both sides.

    (3330)2=(1+R100)2\left(\frac{33}{30}\right)^2 = \left(1 + \frac{R}{100}\right)^2 3330=1+R100\frac{33}{30} = 1 + \frac{R}{100} 1110=1+R100\frac{11}{10} = 1 + \frac{R}{100}
  5. Solve for RR.

    R100=1110−1\frac{R}{100} = \frac{11}{10} - 1 R100=11−1010\frac{R}{100} = \frac{11 - 10}{10} R100=110\frac{R}{100} = \frac{1}{10} R=10010R = \frac{100}{10} R=10R = 10

    The rate of interest is 10% per annum.

    The final answer is 10% P.C.P.A.\boxed{10\% \text{ P.C.P.A.}}.

    Q2. A washing machine was purchased for Rs. 2100. After 1 year the price were reduced by 5%. What will be price of machine after 1 year?

  6. Identify the given values.

    Original Price (P0P_0) = Rs. 2100
    Rate of reduction (rr) = 5% per year
    Time (nn) = 1 year

  7. Calculate the reduction amount.

    Reduction=P0×r100\text{Reduction} = P_0 \times \frac{r}{100} Reduction=2100×5100\text{Reduction} = 2100 \times \frac{5}{100} Reduction=21×5\text{Reduction} = 21 \times 5 Reduction=Rs. 105\text{Reduction} = \text{Rs. } 105
  8. Calculate the price of the machine after 1 year.

    Price after 1 year=Original Price−Reduction\text{Price after 1 year} = \text{Original Price} - \text{Reduction} Price after 1 year=2100−105\text{Price after 1 year} = 2100 - 105 Price after 1 year=Rs. 1995\text{Price after 1 year} = \text{Rs. } 1995

    The final answer is Rs. 1995\boxed{\text{Rs. } 1995}.

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