Rationalize the denominator of the expression (1)/(sqrt(7)+2) and leave the answer in surd form.

The conjugate of $\sqrt{7}+\sqrt{2}$ is $\sqrt{7}-\sqrt{2}$.

$$\frac{1}{\sqrt{7}+\sqrt{2}} \times \frac{\sqrt{7}-\sqrt{2}}{\sqrt{7}-\sqrt{2}}$$

Use the difference of squares formula $(a+b)(a-b) = a^2 - b^2$ for the denominator.

$$\frac{1 \times (\sqrt{7}-\sqrt{2})}{(\sqrt{7}+\sqrt{2})(\sqrt{7}-\sqrt{2})} = \frac{\sqrt{7}-\sqrt{2}}{(\sqrt{7})^2 - (\sqrt{2})^2}$$

$$\frac{\sqrt{7}-\sqrt{2}}{7 - 2} = \frac{\sqrt{7}-\sqrt{2}}{5}$$

The simplified expression in surd form is $\frac{\sqrt{7}-\sqrt{2}}{5}$.

$$\boxed{\frac{\sqrt{7}-\sqrt{2}}{5}}$$

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