Rearrange the inequality to have 0 on one side.

Here are the solutions to the problems:

1) (a) Find the range of values which $\frac{x^2-12}{x} > 1$.

Step 1: Rearrange the inequality to have 0 on one side.

$$\frac{x^2-12}{x} - 1 > 0$$ $$\frac{x^2-12-x}{x} > 0$$ $$\frac{x^2-x-12}{x} > 0$$

Step 2: Factor the numerator.
The quadratic $x^2-x-12$ factors as $(x-4)(x+3)$.

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