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Rewrite the numerator using the exponent rule a^m+n = a^m * aⁿ.

Mathematics

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Question 1.1.1

  1. Rewrite the numerator using the exponent rule am+n=am⋅ana^{m+n} = a^m \cdot a^n.

    2x+5+2x2x=2x⋅25+2x2x\frac{2^{x+5} + 2^x}{2^x} = \frac{2^x \cdot 2^5 + 2^x}{2^x}
  2. Factor out the common term 2x2^x from the numerator.

    2x(25+1)2x\frac{2^x(2^5 + 1)}{2^x}
  3. Cancel out the common term 2x2^x from the numerator and denominator.

    25+12^5 + 1
  4. Calculate the value.

    32+1=3332 + 1 = \boxed{33}

    Question 1.1.2

  5. Rewrite the terms in the numerator to have a common factor.

    2(22x)−7⋅22x−122x−3=22x+1−7⋅22x−122x−3\frac{2(2^{2x}) - 7 \cdot 2^{2x-1}}{2^{2x-3}} = \frac{2^{2x+1} - 7 \cdot 2^{2x-1}}{2^{2x-3}}
  6. Express 22x+12^{2x+1} as 22x−1⋅222^{2x-1} \cdot 2^2.

    22x−1⋅22−7⋅22x−122x−3\frac{2^{2x-1} \cdot 2^2 - 7 \cdot 2^{2x-1}}{2^{2x-3}}
  7. Factor out 22x−12^{2x-1} from the numerator.

    22x−1(22−7)22x−3=22x−1(4−7)22x−3\frac{2^{2x-1}(2^2 - 7)}{2^{2x-3}} = \frac{2^{2x-1}(4 - 7)}{2^{2x-3}}
  8. Simplify the expression in the parenthesis.

    22x−1(−3)22x−3\frac{2^{2x-1}(-3)}{2^{2x-3}}
  9. Use the exponent rule aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    −3⋅2(2x−1)−(2x−3)-3 \cdot 2^{(2x-1) - (2x-3)}
  10. Simplify the exponent.

    −3⋅22x−1−2x+3=−3⋅22-3 \cdot 2^{2x-1-2x+3} = -3 \cdot 2^2
  11. Calculate the final value.

    −3⋅4=−12-3 \cdot 4 = \boxed{-12}

    Question 1.2.1

  12. Rearrange the equation into standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.

    x2−24=5xx^2 - 24 = 5x x2−5x−24=0x^2 - 5x - 24 = 0
  13. Factor the quadratic expression.

    Find two numbers that multiply to -24 and add to -5 (these are -8 and 3).

    (x−8)(x+3)=0(x-8)(x+3) = 0
  14. Set each factor equal to zero and solve for xx.

    x−8=0  ⟹  x=8x-8 = 0 \implies x = 8 x+3=0  ⟹  x=−3x+3 = 0 \implies x = -3

    The solutions are x=8 or x=−3\boxed{x=8 \text{ or } x=-3}.

    Question 1.2.2

  15. Square both sides of the equation to eliminate the square root.

    2x−1=3\sqrt{2x-1} = 3 (2x−1)2=32(\sqrt{2x-1})^2 = 3^2 2x−1=92x-1 = 9
  16. Add 1 to both sides of the equation.

    2x=9+12x = 9 + 1 2x=102x = 10
  17. Divide by 2 to solve for xx.

    x=102x = \frac{10}{2} x=5x = \boxed{5}
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