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Rewrite x2 + 5x + 6 in the form x2 + rx + sx + c.

Mathematics

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Answer

(x + 2)(x + 3)

Step-by-step solution

2 steps
  1. Rewrite x2+5x+6x^2 + 5x + 6 in the form x2+rx+sx+cx^2 + rx + sx + c.

    From the previous steps, we identified that for the trinomial x2+5x+6x^2 + 5x + 6, the two integers rr and ss whose product is 6 and sum is 5 are 2 and 3.
    Therefore, we can rewrite the middle term 5x5x as 2x+3x2x + 3x.

    x2+2x+3x+6x^2 + 2x + 3x + 6
  2. Factorize the expression using associative and distributive properties.

    We will group the terms and factor out the common factors.

    x2+2x+3x+6x^2 + 2x + 3x + 6

    Group the first two terms and the last two terms:

    (x2+2x)+(3x+6)(x^2 + 2x) + (3x + 6)

    Factor out the greatest common factor (HCF) from each group:

    x(x+2)+3(x+2)x(x + 2) + 3(x + 2)

    Now, factor out the common binomial factor (x+2)(x + 2):

    (x+2)(x+3)(x + 2)(x + 3)
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