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Determine the roots of 3x² − 5x − 7 = 0 from the graph.

Mathematics

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Graph of y = 3x² − 5x − 7

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Key points of y = 3x² − 5x − 7
Pointxy
x-intercept−0.910
y-intercept0−7
Minimum0.83−9.08
x-intercept2.570

Step-by-step solution

3 steps
  1. Determine the roots of 3x2−5x−7=03x^2 - 5x - 7 = 0 from the graph.

    The roots of the equation 3x2−5x−7=03x^2 - 5x - 7 = 0 are the x-intercepts of the graph y=3x2−5x−7y = 3x^2 - 5x - 7, which are the points where the curve crosses the x-axis (where y=0y=0).
    From the graph, the curve crosses the x-axis at approximately x=−0.9x = -0.9 and x=2.6x = 2.6.

    a) (i) The roots are x=−0.9 and x=2.6\boxed{x = -0.9 \text{ and } x = 2.6}.

  2. Determine the minimum value of yy from the graph.

    The minimum value of yy for this parabola (which opens upwards) is at its vertex, the lowest point on the curve.
    From the graph, the lowest point on the curve is at y=−9y = -9.

    a) (ii) The minimum value of yy is y=−9\boxed{y = -9}.

  3. Calculate the gradient of the curve at point x=2x = 2.

    To find the gradient of the curve at x=2x=2 from the graph, we need to find the gradient of the tangent line to the curve at x=2x=2. The image provides a calculation using two points on what appears to be a tangent line or a secant line approximating the tangent. The points used are (x1,y1)=(1.30,−10)(x_1, y_1) = (1.30, -10) and (x2,y2)=(3,1.5)(x_2, y_2) = (3, 1.5).

    The formula for the gradient (slope) is:

    m=ΔyΔx=y2−y1x2−x1m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1}

    Substitute the given points:

    m=1.5−(−10)3−1.30m = \frac{1.5 - (-10)}{3 - 1.30} m=1.5+101.70m = \frac{1.5 + 10}{1.70} m=11.51.70m = \frac{11.5}{1.70} m≈6.7647m \approx 6.7647

    Rounding to one decimal place, the gradient is 6.8.

    a) (iii) The gradient of the curve at point x=2x=2 is ≈6.8\boxed{\approx 6.8}.

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