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Simplify the following: 1. (3a+4b)/(10) + (5a-b)/(4); 2. (6y-5x)/(10) - (2x+y)/(5) + x/(3); 3. (5t+1)/(9); 4. (4u+5)/(4) - (3u-5)/(2); 5. (x-3)/(3) - (x+2)/(5)

Mathematics

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Here are the solutions for problems 4 and 5:

4. Simplify u+54−3u−52\frac{u+5}{4} - \frac{3u-5}{2}

  1. Find the least common multiple (LCM) of the denominators 4 and 2.

    The LCM is 4.

  2. Rewrite the second fraction with the common denominator.

    3u−52=2(3u−5)2×2=6u−104\frac{3u-5}{2} = \frac{2(3u-5)}{2 \times 2} = \frac{6u-10}{4}
  3. Subtract the fractions.

    u+54−6u−104=(u+5)−(6u−10)4\frac{u+5}{4} - \frac{6u-10}{4} = \frac{(u+5) - (6u-10)}{4}
  4. Distribute the negative sign and combine like terms in the numerator.

    u+5−6u+104=(u−6u)+(5+10)4\frac{u+5-6u+10}{4} = \frac{(u-6u) + (5+10)}{4} −5u+154\frac{-5u+15}{4}

    The simplified expression is −5u+154\boxed{\frac{-5u+15}{4}}.

    5. Simplify x−33−x+25\frac{x-3}{3} - \frac{x+2}{5}

  5. Find the LCM of the denominators 3 and 5.

    The LCM is 15.

  6. Rewrite each fraction with the common denominator.

    x−33=5(x−3)5×3=5x−1515\frac{x-3}{3} = \frac{5(x-3)}{5 \times 3} = \frac{5x-15}{15} x+25=3(x+2)3×5=3x+615\frac{x+2}{5} = \frac{3(x+2)}{3 \times 5} = \frac{3x+6}{15}
  7. Subtract the fractions.

    5x−1515−3x+615=(5x−15)−(3x+6)15\frac{5x-15}{15} - \frac{3x+6}{15} = \frac{(5x-15) - (3x+6)}{15}
  8. Distribute the negative sign and combine like terms in the numerator.

    5x−15−3x−615=(5x−3x)+(−15−6)15\frac{5x-15-3x-6}{15} = \frac{(5x-3x) + (-15-6)}{15} 2x−2115\frac{2x-21}{15}

    The simplified expression is 2x−2115\boxed{\frac{2x-21}{15}}.

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