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Mathematics

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  1. The problem asks to solve for xx in the equation 3x−7=143x - 7 = 14.

  2. Add 7 to both sides of the equation to isolate the term with xx.

    3x−7+7=14+73x - 7 + 7 = 14 + 7
    3x=213x = 21

  3. Divide both sides by 3 to solve for xx.

    3x3=213\frac{3x}{3} = \frac{21}{3}
    x=7x = 7

    x=7x = 7

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  4. The problem asks to simplify the expression 5(y+2)−3y5(y + 2) - 3y.

  5. Distribute the 5 to the terms inside the parentheses.

    5×y+5×2−3y5 \times y + 5 \times 2 - 3y
    5y+10−3y5y + 10 - 3y

  6. Combine like terms (the terms with yy).

    (5y−3y)+10(5y - 3y) + 10
    2y+102y + 10

    2y+102y + 10

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  7. The problem asks to find the area of a rectangle with length l=8l = 8 cm and width w=5w = 5 cm.

  8. Use the formula for the area of a rectangle, which is Area = length × width.

    Area =l×w= l \times w

  9. Substitute the given values for length and width into the formula.

    Area =8 cm×5 cm= 8 \text{ cm} \times 5 \text{ cm}

  10. Calculate the area.

    Area =40 cm2= 40 \text{ cm}^2

    40 cm240 \text{ cm}^2
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