Given A, B, and C matrices, evaluate A-B+C.

Add $\frac{1}{3}$ to both sides:

Multiply by $\frac{6}{13}$:

Add $\frac{1}{3}$ to both sides:

Multiply by $\frac{6}{13}$:

We have $x > -\frac{22}{13}$ and $x \le \frac{8}{13}$.
The solution set is $-\frac{22}{13} < x \le \frac{8}{13}$.

The interval is $(-\frac{22}{13}, \frac{8}{13}]$.
On the number line, place an open circle at $-\frac{22}{13}$ (approximately $-1.69$) and a closed circle at $\frac{8}{13}$ (approximately 0.62). Shade the region between these two points.

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      -2          -22/13          -1           0          8/13         1
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-\frac{22}{13} < x \le \frac{8}{13}