Describe how you would help your learners in a primary class to multiply the following using number line. 7 x 1/3, 10 x 2/5, 2 x 4/5, 3 x 1/4, 4 x 1/4.

Mathematics
Describe how you would help your learners in a primary class to multiply the following using number line. 7 x 1/3, 10 x 2/5, 2 x 4/5, 3 x 1/4, 4 x 1/4.

ScanSolve AI Answer

Answer

8401

Step 1: Set up the multiplication of 271271 by 3131.

\begin{array}{r@{}r@{}r@{}r} & & 2 & 7 & 1 \\ \times & & & 3 & 1 \\ \hline \end{array}

Step 2: Multiply 271271 by 11 (ones place).

Formula: 271×1=271271 \times 1 = 271

Substitute: 200×1=200200 \times 1 = 200, 70×1=7070 \times 1 = 70, 1×1=11 \times 1 = 1

Simplify: 200+70+1=271200 + 70 + 1 = 271

Write 271271 aligned to the right:

\begin{array}{r@{}r@{}r@{}r@{}r} & & & 2 & 7 & 1 \\ \times & & & & 3 & 1 \\ \hline & & & 2 & 7 & 1 \\ \end{array}

Step 3: Multiply 271271 by 33 (tens place), then shift left by 11 position (add a zero).

Formula: 271×3=?271 \times 3 = ?, then ×10\times 10.

First, 271×3271 \times 3:

1×3=31 \times 3 = 3

7×3=217 \times 3 = 21 (write 11, carry 22)

2×3+2=82 \times 3 + 2 = 8

So, 813813. Then shift: 81308130.

Write 813813 starting under the tens column:

\begin{array}{r@{}r@{}r@{}r@{}r@{}r} & & & & 2 & 7 & 1 \\ \times & & & & & 3 & 1 \\ \hline & & & & 2 & 7 & 1 \\ + & & 8 & 1 & 3 & & \\ \hline \end{array}

Step 4: Add the partial products.

Formula: 271+8130=?271 + 8130 = ?

Column by column, right to left:

Units: 1+0=11 + 0 = 1

Tens: 7+3=107 + 3 = 10 (write 00, carry 11)

Hundreds: 2+1+1=42 + 1 + 1 = 4

Thousands: 8=88 = 8

Simplify: 84018401

\begin{array}{r@{}r@{}r@{}r@{}r@{}r} & & & & 2 & 7 & 1 \\ \times & & & & & 3 & 1 \\ \hline & & & & 2 & 7 & 1 \\ + & & 8 & 1 & 3 & 0 & \\ \hline & 8 & 4 & 0 & 1 & & \\ \end{array}

8401

Was this helpful?

Need help with your own homework?

Get instant step-by-step solutions to any question. Free to start.

Ask Your Question
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.

More Mathematics Questions

QचQर्तियों की सहायता से निम्नांकित का मान ज्ञात कीजिए । (i) (-4)+(-5) (iii) (-11)+(-7) (v) (+4)+(+2)…QKando limited received an invoice from a supplier for K28500. The terms of payment offered were a 5%…QGive me paper one of mathematics kcse 2024 section A questions and answersQPlease Draw Using a ruler and a pair of compases Only construct the following angles 5° 135°QJournal riyazi TCS School maliya malayatti riyasi chapter ka naam hai aur is chapter mein 4.1 exerci…
See all Mathematics questions →

Still have questions?

Quick Answer

Set up the multiplication of 271 by 31. r@r@r@r & & 2 & 7 & 1 \\ × & & & 3 & 1 \\ Step 2: Multiply 271 by 1 (ones place).

Describe how you would help your learners in a primary class to multiply the following using number line. 7 x 1/3, 10 x 2/5, 2 x 4/5, 3 x 1/4, 4 x 1/4.
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Step 1: Set up the multiplication of 271 by 31. r@r@r@r & & 2 & 7 & 1 \\ × & & & 3 & 1 \\ Step 2: Multiply 271 by 1 (ones place). Formula: 271 × 1 = 271 Substitute: 200 × 1 = 200, 70 × 1 = 70, 1 × 1 = 1 Simplify: 200 + 70 + 1 = 271 Write 271 aligned to the right: r@r@r@r@r & & & 2 & 7 & 1 \\ × & & & & 3 & 1 \\ & & & 2 & 7 & 1 \\ Step 3: Multiply 271 by 3 (tens place), then shift left by 1 position (add a zero). Formula: 271 × 3 = ?, then × 10. First, 271 × 3: 1 × 3 = 3 7 × 3 = 21 (write 1, carry 2) 2 × 3 + 2 = 8 So, 813. Then shift: 8130. Write 813 starting under the tens column: r@r@r@r@r@r & & & & 2 & 7 & 1 \\ × & & & & & 3 & 1 \\ & & & & 2 & 7 & 1 \\ + & & 8 & 1 & 3 & & \\ Step 4: Add the partial products. Formula: 271 + 8130 = ? Column by column, right to left: Units: 1 + 0 = 1 Tens: 7 + 3 = 10 (write 0, carry 1) Hundreds: 2 + 1 + 1 = 4 Thousands: 8 = 8 Simplify: 8401 r@r@r@r@r@r & & & & 2 & 7 & 1 \\ × & & & & & 3 & 1 \\ & & & & 2 & 7 & 1 \\ + & & 8 & 1 & 3 & 0 & \\ & 8 & 4 & 0 & 1 & & \\ 8401