Simplify 3x² + 2x + 6 =0

Mathematics

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This is a quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0, where a=3a=3, b=2b=2, and c=6c=6. To simplify or solve this equation, we can use the quadratic formula:

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
  1. Substitute the values of a, b, and c into the quadratic formula.

    x=−(2)±(2)2−4(3)(6)2(3)x = \frac{-(2) \pm \sqrt{(2)^2 - 4(3)(6)}}{2(3)}
  2. Simplify the expression under the square root (the discriminant).

    x=−2±4−726x = \frac{-2 \pm \sqrt{4 - 72}}{6} x=−2±−686x = \frac{-2 \pm \sqrt{-68}}{6}
  3. Simplify the square root of the negative number.

    We can write −68\sqrt{-68} as 68i\sqrt{68}i, where ii is the imaginary unit (i=−1i = \sqrt{-1}).

    x=−2±68i6x = \frac{-2 \pm \sqrt{68}i}{6}
  4. Simplify 68\sqrt{68}.

    Since 68=4×1768 = 4 \times 17, we have 68=4×17=217\sqrt{68} = \sqrt{4 \times 17} = 2\sqrt{17}.

    x=−2±217i6x = \frac{-2 \pm 2\sqrt{17}i}{6}
  5. Divide both terms in the numerator by the denominator.

    x=−26±217i6x = \frac{-2}{6} \pm \frac{2\sqrt{17}i}{6} x=−13±173ix = -\frac{1}{3} \pm \frac{\sqrt{17}}{3}i

    The solutions are complex numbers.

    The simplified form of the equation is:

    x=−13±173ix = -\frac{1}{3} \pm \frac{\sqrt{17}}{3}i
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