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Simplify: [sin x cosy + cos x siny]2 + [cos x cosy - sin x siny]2

Mathematics

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Step-by-step solution

3 steps

Here's how to simplify the expression:

  1. Identify the trigonometric sum identities.

    The expression contains two parts that match the sum identities for sine and cosine:
    The first term, sin⁡xcos⁡y+cos⁡xsin⁡y\sin x \cos y + \cos x \sin y, is the expansion of sin⁡(x+y)\sin(x+y).
    The second term, cos⁡xcos⁡y−sin⁡xsin⁡y\cos x \cos y - \sin x \sin y, is the expansion of cos⁡(x+y)\cos(x+y).

  2. Substitute the identities into the expression.

    [sin⁡xcos⁡y+cos⁡xsin⁡y]2+[cos⁡xcos⁡y−sin⁡xsin⁡y]2[\sin x \cos y + \cos x \sin y]^2 + [\cos x \cos y - \sin x \sin y]^2

    Becomes:

    [sin⁡(x+y)]2+[cos⁡(x+y)]2[\sin(x+y)]^2 + [\cos(x+y)]^2

    This can be written as:

    sin⁡2(x+y)+cos⁡2(x+y)\sin^2(x+y) + \cos^2(x+y)
  3. Apply the Pythagorean identity.

    Recall the fundamental trigonometric identity: sin⁡2θ+cos⁡2θ=1\sin^2 \theta + \cos^2 \theta = 1.
    In this case, θ=(x+y)\theta = (x+y).

    sin⁡2(x+y)+cos⁡2(x+y)=1\sin^2(x+y) + \cos^2(x+y) = 1

    The simplified expression is:

    11
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