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Simplify the algebraic expression 5x2/(x2-2x) - (x2-4)/(x2+2x) Find the value of x in the diagram below.

Mathematics

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Here are the solutions to the problems:

: Simplify fraction expression

  1. Convert mixed numbers to improper fractions.

    634=2746\frac{3}{4} = \frac{27}{4} 2415=34152\frac{4}{15} = \frac{34}{15} 123=531\frac{2}{3} = \frac{5}{3}
  2. Evaluate the expression inside the parenthesis.

    2415−123=3415−53=3415−2515=915=352\frac{4}{15} - 1\frac{2}{3} = \frac{34}{15} - \frac{5}{3} = \frac{34}{15} - \frac{25}{15} = \frac{9}{15} = \frac{3}{5}
  3. Perform the "of" operation (multiplication).

    23 of 634=23×274=5412=92\frac{2}{3} \text{ of } 6\frac{3}{4} = \frac{2}{3} \times \frac{27}{4} = \frac{54}{12} = \frac{9}{2}
  4. Perform the division.

    92÷35=92×53=456=152\frac{9}{2} \div \frac{3}{5} = \frac{9}{2} \times \frac{5}{3} = \frac{45}{6} = \frac{15}{2}

    The simplified expression is 152\boxed{\frac{15}{2}} or 712\boxed{7\frac{1}{2}}.

    : Evaluate and leave your answer in standard form

  5. Perform the multiplication in the numerator.

    4.56×3.6=16.4164.56 \times 3.6 = 16.416
  6. Perform the division.

    16.4160.12=1641.612=136.8\frac{16.416}{0.12} = \frac{1641.6}{12} = 136.8
  7. Express the answer in standard form.

    136.8=1.368×102136.8 = 1.368 \times 10^2

    The evaluated value in standard form is 1.368×102\boxed{1.368 \times 10^2}.

    : Calories burned per hour

  8. Divide the total calories burned by the total hours.

    Calories per hour=Total caloriesTotal hours\text{Calories per hour} = \frac{\text{Total calories}}{\text{Total hours}} Calories per hour=856 calories4 hours\text{Calories per hour} = \frac{856 \text{ calories}}{4 \text{ hours}}
  9. Calculate the value.

    Calories per hour=214 calories/hour\text{Calories per hour} = 214 \text{ calories/hour}

    Bongo burns 214 calories per hour\boxed{214 \text{ calories per hour}}.

    : Simplify the algebraic expression

  10. Factor the denominators and numerators.

    5x2x2−2x−x2−4x2+2x=5x2x(x−2)−(x−2)(x+2)x(x+2)\frac{5x^2}{x^2-2x} - \frac{x^2-4}{x^2+2x} = \frac{5x^2}{x(x-2)} - \frac{(x-2)(x+2)}{x(x+2)}
  11. Simplify each term by canceling common factors.

    5xx−2−x−2x\frac{5x}{x-2} - \frac{x-2}{x}
  12. Find a common denominator and combine the fractions.

    The common denominator is x(x−2)x(x-2).

    5x⋅xx(x−2)−(x−2)(x−2)x(x−2)=5x2−(x2−4x+4)x(x−2)\frac{5x \cdot x}{x(x-2)} - \frac{(x-2)(x-2)}{x(x-2)} = \frac{5x^2 - (x^2 - 4x + 4)}{x(x-2)}
  13. Expand and simplify the numerator.

    5x2−x2+4x−4x(x−2)=4x2+4x−4x(x−2)\frac{5x^2 - x^2 + 4x - 4}{x(x-2)} = \frac{4x^2 + 4x - 4}{x(x-2)}
  14. Factor out common terms in the numerator.

    4(x2+x−1)x(x−2)\frac{4(x^2 + x - 1)}{x(x-2)}

    The simplified expression is 4(x2+x−1)x(x−2)\boxed{\frac{4(x^2 + x - 1)}{x(x-2)}}.

    : Find the value of x in the diagram

  15. Use the property that the exterior angle of a triangle is equal to the sum of the two opposite interior angles.

    (x+17∘)+(2x+7∘)=9x∘(x+17^\circ) + (2x+7^\circ) = 9x^\circ
  16. Simplify and solve for xx.

    3x+24=9x3x + 24 = 9x 24=9x−3x24 = 9x - 3x 24=6x24 = 6x x=246x = \frac{24}{6} x=4x = 4

    The value of xx is 4\boxed{4}.

    : Rectangle dimensions

  17. Define the dimensions.

    Let the width of the rectangle be ww.
    The length ll is three times its width, so l=3wl = 3w.

  18. Use the formula for the perimeter of a rectangle.

    P=2(l+w)P = 2(l+w)

    Given P=24P = 24 cm.

    24=2(3w+w)24 = 2(3w + w)
  19. Solve for ww.

    24=2(4w)24 = 2(4w) 24=8w24 = 8w w=248w = \frac{24}{8} w=3 cmw = 3 \text{ cm}

    The width of the rectangle is 3 cm\boxed{3 \text{ cm}}.

    : Find the vector r

  20. Add vectors q\mathbf{q} and p\mathbf{p}.

    q+p=(25)+(23)=(2+25+3)=(48)\mathbf{q} + \mathbf{p} = \begin{pmatrix} 2 \\ 5 \end{pmatrix} + \begin{pmatrix} 2 \\ 3 \end{pmatrix} = \begin{pmatrix} 2+2 \\ 5+3 \end{pmatrix} = \begin{pmatrix} 4 \\ 8 \end{pmatrix}
  21. Multiply the resulting vector by 12\frac{1}{2}.

    r=12(q+p)=12(48)=(12×412×8)=(24)\mathbf{r} = \frac{1}{2}(\mathbf{q} + \mathbf{p}) = \frac{1}{2} \begin{pmatrix} 4 \\ 8 \end{pmatrix} = \begin{pmatrix} \frac{1}{2} \times 4 \\ \frac{1}{2} \times 8 \end{pmatrix} = \begin{pmatrix} 2 \\ 4 \end{pmatrix}

    The vector r\mathbf{r} is (24)\boxed{\begin{pmatrix} 2 \\ 4 \end{pmatrix}}.

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