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Simplify the expression 2n+2 x 8ⁿ-142n

Mathematics

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  1. Express all bases as powers of 2.

    2n+2×8n−142n=2n+2×(23)n−1(22)2n\frac{2^{n+2} \times 8^{n-1}}{4^{2n}} = \frac{2^{n+2} \times (2^3)^{n-1}}{(2^2)^{2n}}

  2. Apply the power rule (ab)c=abc(a^b)^c = a^{bc}.

    =2n+2×23(n−1)22(2n)=2n+2×23n−324n= \frac{2^{n+2} \times 2^{3(n-1)}}{2^{2(2n)}} = \frac{2^{n+2} \times 2^{3n-3}}{2^{4n}}

  3. Step 3

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